regardin the code

[Former Member]

write: / 'rajesh'.

new-page.

write: / 'rajesh***'.

top-of-page.

write: / '******rajesh*****'.

can u tell me which of the form it will trigger

can u give me the seqence clearly step by step plz

[Former Member]

'******rajesh*****'.

'rajesh'.

'******rajesh*****'.

'rajesh***'.

REGARDS

SHIBA DUTTA

[SantoshKallem]

******rajesh*******

rajesh

******rajesh*******

rajesh*******

check it out.

[Former Member]

SORY I WAS NOT CLEAR IN MY PREV ANSWER.

FIRST WRITE STATEMENT TRIGGER TOP-OF-PAGE SO IT IS PRINTING TOP-OF-PAGE THEN IT WILL WRITE ******rajesh***** THEN IT WILL AGAIN COME BACK TO THE FIRST WRITE STATEMENT AND WRITE 'rajesh***. AGAIN NEW-PAGE TRIGGER TOP-OF-PAGE AND WRITE ******rajesh***** AND THEN IT WILL WRITE AFTER NEW-PAGE. 'rajesh***

REGARDS

SHIBA DUTTA

[former_member194669]

Hi,

1. top-of-page.

write: / '******rajesh*****'.

2. write: / 'rajesh'.

3.new-page.

write: / 'rajesh***'.

aRs

[Former Member]

The ans given by Shiba is write...

1. it will trigger Top-of-page event

2. it will display ur write: / 'rajesh'. since this statement is present for start-of-selection event

3. since u have given the event as New-page so again the top-of-page event is triggered & then ur write: / 'rajesh***'. statement is executed & displayed in the list.

if this has helped then pls give the points to this ans..

[Former Member]

hi

first the top of page evnt gets triggered irrespective of the position it has been declaredtop-of-page.

write: / '******rajesh*****'.

and the statemment rajesh write: / 'rajesh'.

and finally the new page evnt gets triggered and the statemnt is written to the list

new-page.

write: / 'rajesh***'.

regards,

kiran kumar k

[Former Member]

Hi rajesh....

When ever the first write statement

(WRITE: / 'rajesh'.)

is encountered execution of that write will be suspended and the control goes to top-of-page event and the write statement in that event

( WRITE: / '******rajesh*****'.)

will be executed, after that the write statement

(WRITE: / 'rajesh'.) will be executed.

now new-line is executed so it will cause a page break.

the next output statements will be printed in the next page. but when the next write statement

(WRITE: / 'rajesh***'.)

is encountered, the control goes to the top-of-page event because it is the first output statement to be executed in that page and the top-of-page will be executed after that the statement:

WRITE: / 'rajesh***'.

will be executed.

So the output consists of 2 pages sa below:

Page1:

******rajesh*****

rajesh

page2:

******rajesh*****

rajesh***

Suresh......

[Former Member]

thanks a lot

[Former Member]

write: / 'rajesh'.


new-page.
write: / 'rajesh***'.

top-of-page.
write: / '*******rajesh******'.

For this ..you need to understand new-page concept here thats the main key for 4 write statements in the o/p.

during the compilation  by default before the first write statement is triggered 
TOP-OF-PAGE  is triggered .

1.   '*******rajesh******'.

2. since the default line count is 33-36 in the report statement start-of-selection is
triggered and write statement is triggered which is 

'rajesh'

3. Now u are forcing the new-page statement so the system now treats this command as to be print in the new page 

so for this again u have top-of-page for the new page this is important 

<b>so again top-of-page is triggered before the write of of new -page .</b>

once again top-of-page is triggered .
'*******rajesh******'.

4 . followed by 
'rajesh***'.

new page write statement .

Regards,

vijay.

You have total 4 o/ps .

*******rajesh******  
rajesh               
          
           
*******rajesh******    " ---> repeated for new page .
rajesh***