itab

[Former Member]

hi,

i have 2 fields in itab1 and 3 fields in itab2 with data.

i want a itab where all 5 fields with data should be there in this new itab.

how i will do it?

can any one help me?

thanks

Santosini

[Former Member]

Hi,

Suppose if you have mininmum 2 fields same in both the itabs then you can pass.

ITAB[] = ITAB2[].

LOOP AT ITAB1.

MOVE : ITAB2-field1 TO itab-field1,

ITAB2-field2 TO itab-field2,

APPEND ITAB.

CLEAR ITAB.

ENDLOOP.

[Former Member]

Hi,

Suppose if you have mininmum 2 fields same in both the itabs then you can pass.

ITAB[] = ITAB2[].

LOOP AT ITAB1.

MOVE : ITAB2-field1 TO itab-field1,

ITAB2-field2 TO itab-field2,

APPEND ITAB.

CLEAR ITAB.

ENDLOOP.

[Former Member]

Hi,

You can do like this.

Itab1 with 2 fields.(Heeader data)

itab2 with 3 fields.( Item data)

itab3 wiht 5 fields.

sort itab1 by key.

sort itab2 by key.

loop at itab2.

read table itab1 with key field1 = itab2-field binary search.

if sy-subrc = 0.

move itab2 data to itab3.

move itab1 data to itab3

append itab3.

endif.

endloop.

hope this helps.

Reward if helpful.

Regards

Sourabh

[Former Member]

Hi,

Delcare the 3 internal tables.

If there is a common field in itab1 and itab2, then

loop at itab1.

move-corresponding itab1 to itab3.

read table itab2 with itab1-field = itab2-field.

"field is common field

if sy-subrc = 0.

itab3-field4 = itab2-field1.

itab3-field5 = itab2-field2.

append itab3.

else.

append itab3.

itab3-field4 = itab2-field1.

itab3-field5 = itab2-field2

append itab3.

endif.

endloop.

reward.

[Former Member]

thank you its been solved.