Double click not working in python

[Former Member]

Hi,

I'm trying to access information by double click on a cell and it is not working. After the entering into the screen i'm unable to print any details. the automation fails.

session.findById("wnd[0]/usr/cntlIMAGE_CONTAINER/shellcont/shell/shellcont[0]/shell").selectedNode = "0000000022"
session.findById("wnd[0]/usr/cntlIMAGE_CONTAINER/shellcont/shell/shellcont[0]/shell").doubleClickNode("0000000022")
session.findById("wnd[0]/usr/ctxtER_STAT").text = "R"
session.findById("wnd[0]/usr/ctxtER_BP2-LOW").text = b+"*"
session.findById("wnd[0]/usr/ctxtER_RTN_D-LOW").text = today
session.findById("wnd[0]/usr/ctxtER_RTN_D-HIGH").text = today
session.findById("wnd[0]/tbar[1]/btn[8]").press()
---Code works fine until here The screen with the information reflects-- The below code does not work-            
print("In the details page")
session.findById("wnd[0]/usr/lbl[3,5]").setFocus()
print("focus")
session.findById("wnd[0]/usr/lbl[3,5]").caretPosition = 0
session.findById("wnd[0]").sendVKey(2)
print("Success")

Attached is image of the view. I'm unable to change this to a grid view.

Regards,
Renato.

[Sandra_Rossi]

Here is the image posted by the OP:

[Sandra_Rossi]

You don't explain what goal you want to achieve.

Anyway, if you expect to set the cursor at the output-only text ("label") which starts at column 3, row 5, then this code is fine:

session.findById("wnd[0]/usr/lbl[3,5]").setFocus()

If you want to position at "RR" (output-only text starting at column 22, row 0), then you should do:

session.findById("wnd[0]/usr/lbl[22,0]").setFocus()

Concerning the double-click, it corresponds to pressing F2, so this code is fine:

session.findById("wnd[0]").sendVKey 2 ' Press F2

[Former Member]

Hi Sandra,

I'm trying to double click on the label. Which would in turn take me to the next screen. The challenge i'm facing it that it is not recognizing either the

session.findById("wnd[0]/usr/lbl[3,5]").setFocus()

Or

session.findById("wnd[0]").sendVKey 2 ' Press F2

I'm not sure why it is not working.

There is a tiny check box beside the label. I have tried setting that as true as well and it still does not work. Which is quite puzzeling for me.

Regards,

Renato.

[Sandra_Rossi]

I don't understand why your code doesn't work and my code works, although it has exactly the same lines of code.

Are you sure that there's a label starting at column 3 (4th column) and row 5 (6th row)? If no and if SAP GUI doesn't send an error message, then it means that you handle all errors, so you will have big issues to troubleshoot your code! Just don't handle all errors.

What checkbox are you talking about?

Could you please provide screenshots corresponding to what you expect?

[Former Member]

This is the code for the check box and box is being highlighted but it does not get selected.

session.findById("wnd[0]/usr/chk[1,5]").selected = True

[Former Member]

check-box.png

This is the check box image and im not trying to catch any error.

I tired selecting all the checkbox using the below code and it does not work.

session.findById("wnd[0]/tbar[1]/btn[5]").press()

Not sure it is a problem with the GUI. When i record it i find the options are correct.

[Sandra_Rossi]

Here is the image posted by the OP:

[Sandra_Rossi]

It doesn't look like the original question, which was about double-clicking an output-only text field. Is this solved now?

I don't understand why you show all these different codes. Could you just show what code the Script Recorder produce when you click the checkbox please?

[Sandra_Rossi]

I just did the recording. I confirm that it get the same and it works for me:

session.findById("wnd[0]/usr/chk[1,5]").selected = True