String operation

[Former Member]

Hi Abapers,

Please tell me how to replace first 4 characters of one variable with some other characters.

[Former Member]

Hi,

Try using Replace statement.

regards,

Santosh Thorat

[Former Member]

Hi,

You can use REPLACE ALL..

Ex..

REPLACE ALL OCCURRENCES OF ',' IN temp WITH ''.

Thanks

naren

[Former Member]

Hi,

have a look at this link,

http://help.sap.com/saphelp_46c/helpdata/en/71/52604ff6f011d2961c00a0c930660b/frameset.htm

[Former Member]

hi shruti,

a string in a field with a different string, use the REPLACE statement.

REPLACE <str1> WITH <str2> INTO <c> [LENGTH <l>].

The statement searches the field <c> for the first occurrence of the first <l> positions of the pattern <str1>. If no length is specified, it searches for the pattern <str1> in its full length.

Then, the statement replaces the first occurrence of the pattern <str1> in field <c> with the string <str2>. If a length <l> was specified, only the relevant part of the pattern is replaced.

If the return code value of the system field SY-SUBRC is set to 0, this indicates that <str1> was found in <c> and replaced by <str2>. A return code value other than 0 means that nothing was replaced. <str1>, <str2>, and <len> can be variables.

*************************

example:

DATA: T(10) VALUE 'abcdefghij',

STRING LIKE T,

STR1(4) VALUE 'cdef',

STR2(4) VALUE 'klmn',

STR3(2) VALUE 'kl',

STR4(6) VALUE 'klmnop',

LEN TYPE I VALUE 2.

STRING = T.

WRITE STRING.

REPLACE STR1 WITH STR2 INTO STRING.

WRITE / STRING.

STRING = T.

REPLACE STR1 WITH STR2 INTO STRING LENGTH LEN.

WRITE / STRING.

STRING = T.

REPLACE STR1 WITH STR3 INTO STRING.

WRITE / STRING.

STRING = T.

REPLACE STR1 WITH STR4 INTO STRING.

WRITE / STRING.

The output appears as follows:

abcdefghij

abklmnghij

abklmnefgh

abklghij

abklmnopgh

***********************

reward if useful..

[Former Member]

Hi,

Check the mentioned examples you will get a clear picture.

*EG1:

DATA STR1(36).

STR1 = 'APPLE & ORANGE & BANANA'.

REPLACE '&' WITH ' . ' INTO STR1.

WRITE:/ STR1.

*EG2:

Data p(6) value 'ABCABC'.

Replace 'ABC' with 'DEF' into p.

Write:/ p.

Reward if helpful.

Regards,

Harini.S

[Former Member]

I want to add 10 spaces to the variable.How to do this?

[Former Member]

Hi Shruti,

Data: str1(10) type c value 'abcdefghij',

str2(4) type c value 'wxyz'.

shift str1 by 4 places.

concatenate str2 str1 into str1.

condense str1 no-gaps.

[Former Member]

Hi,

Try this..

DATA: BEGIN OF S_TEST,

CHAR(10),

VALUE(10),

END OF S_TEST.

S_TEST-VALUE = 'TeST'.

**Now S_TEST will have 10 blank places in front..

Thanks

naren

[rajesh_akarte2]

Hi Shruti ,

Go through this example.

DATA v1(10) TYPE C value '1234567891'.

REPLACE SECTION OFFSET 0 LENGTH 1 OF v1 WITH 'H'

IN CHARACTER MODE.

REPLACE SECTION OFFSET 1 LENGTH 1 OF v1 WITH 'H'

IN CHARACTER MODE.

REPLACE SECTION OFFSET 2 LENGTH 1 OF v1 WITH 'H'

IN CHARACTER MODE.

REPLACE SECTION OFFSET 3 LENGTH 1 OF v1 WITH 'H'

IN CHARACTER MODE.

WRITE: v1.

please reward the points if helpful.

Regards,

Rajesh Akarte

[Former Member]

Ok. If the number of spaces I want to add is not a constant. Suppose some times 20 sometimes 21 sometimes 30. It depends on the value of PO number.

[Former Member]

HI,

Try this..give the input and it will put that number of blank spaces in the front.

PARAMETERS: P_TIMES TYPE I.


START-OF-SELECTION.

DATA: V_STRING TYPE STRING.

**default value.
V_STRING= 'TEST'.

*" Concatenate blank according to the selectionscreen parameter.
do p_times times.

  concatenate space v_string into v_string.

enddo.

write: / v_string.

Thanks

naren

[Former Member]

Thanks Naren. Your logic of taking a structure worked out.

[Former Member]

You are welcome

Regards

Naren