String Modifications

[Former Member]

Hi Experts,

I have a requirement to take first 10 characters of a string including spaces and numbers but eliminating punctuations marks.

So can someone please help me with the punctuation part i.e is there a way to include all punctuations or do i have to write explicitly all of them.

Thanks in anticipation.

[Former Member]

First of all welcome to SDN and please read the engagement rules ..

Do search before posting such basic questions

Still i am giving you this code .. Not exactly what you want .. but i am sure you can tweak it to your requirements ..

REPORT zstring. 
DATA : ipstr TYPE string. 
DATA : opstr TYPE string. 
DATA : len TYPE i VALUE 0. 
DATA : ch TYPE char1. 
DATA : num TYPE i VALUE 0.   "No of Characters to be taken 
DATA : pos TYPE char3.       "Position of Char in the Input String 
*Input string 
ipstr = '<FT><H><T> Line Clearance </></></>'. 
*Removing only "</>" 
REPLACE ALL OCCURRENCES OF '</>' IN ipstr WITH ' '. 
*Removing only "<" 
REPLACE ALL OCCURRENCES OF '<' IN ipstr WITH ' '. 
CONDENSE ipstr. 
*Length of Input String 
len = STRLEN( ipstr ). 
  DO len TIMES. 
*Char by Char 
  ch = ipstr+pos(1). 
  pos = pos + 1. 
*Scan each char in input String for ">" 
  FIND '>' IN ch IGNORING CASE. 
  IF sy-subrc = 0. 
    num = len - pos. 
*Output String 
    opstr = ipstr+pos(num). 
  ENDIF. 
ENDDO. 
  WRITE :/ opstr.   

This will help you to modify any type of strings .. in the code i have pasted it removes HTML tags .. instead of that just give the punctuation marks ..

Hope this answer helps you

Regards ..

Manthan

[Former Member]

Suppose

L_STR = ' 123456789'.

then do like this...

L_str1 = l_str+0(10).

[manthanraja]

First of all welcome to SDN and please read the engagement rules ..

Do search before posting such basic questions

Still i am giving you this code .. Not exactly what you want .. but i am sure you can tweak it to your requirements ..

REPORT zstring. 
DATA : ipstr TYPE string. 
DATA : opstr TYPE string. 
DATA : len TYPE i VALUE 0. 
DATA : ch TYPE char1. 
DATA : num TYPE i VALUE 0.   "No of Characters to be taken 
DATA : pos TYPE char3.       "Position of Char in the Input String 
*Input string 
ipstr = '<FT><H><T> Line Clearance </></></>'. 
*Removing only "</>" 
REPLACE ALL OCCURRENCES OF '</>' IN ipstr WITH ' '. 
*Removing only "<" 
REPLACE ALL OCCURRENCES OF '<' IN ipstr WITH ' '. 
CONDENSE ipstr. 
*Length of Input String 
len = STRLEN( ipstr ). 
  DO len TIMES. 
*Char by Char 
  ch = ipstr+pos(1). 
  pos = pos + 1. 
*Scan each char in input String for ">" 
  FIND '>' IN ch IGNORING CASE. 
  IF sy-subrc = 0. 
    num = len - pos. 
*Output String 
    opstr = ipstr+pos(num). 
  ENDIF. 
ENDDO. 
  WRITE :/ opstr.   

This will help you to modify any type of strings .. in the code i have pasted it removes HTML tags .. instead of that just give the punctuation marks ..

Hope this answer helps you

Regards ..

Manthan

[Former Member]

Hi ,

Please see my question " I have asked do i need to explictly give all the punctuations marks or is there is some other way round".

Anyways thanks for ur Advise and Help.

[SuhaSaha]

Hello,

Which version of SAP are you in ?

If you have Reg-ex available then you can make use of [:punct:]

E.g.,

REPLACE ALL OCCURENCES OF REGEX [:punct:] IN V_STRING WITH ` `.

BR,

Suhas

Edited by: Suhas Saha on Feb 23, 2010 3:00 PM

[Former Member]

Hi Paresh,

the correct format would be,

REPLACE ALL OCCURRENCES OF REGEX '[[:punct:]]' IN v_string WITH ''.

Regards,

Herwin.

Edited by: Herwin Wilmet Dsouza on Feb 23, 2010 11:11 AM

[Former Member]

Answered.