sorting the internal table I'm getting ......

[Former Member]

While sorting the internal table I'm getting one of the columns not sorted .... why is that? for example

A B C

9 2 11

4 9 10

8 3 7

using ---> sort itab by A B C. gives me this

A B C

4 2 7

8 9 10

9 3 11

please help?

[Former Member]

hi Essa,

It would be better if you could sort it with key fields .. and more over the order in which you might have used the sort statement is

sort ITAB by B A C.

Note : Please close your previous theread by marking helpful answers

Regards,

Santosh

[Former Member]

hi Essa,

It would be better if you could sort it with key fields .. and more over the order in which you might have used the sort statement is

sort ITAB by B A C.

Note : Please close your previous theread by marking helpful answers

Regards,

Santosh

[seshatalpasai_madala]

Hi,

When you sort, sort operation will follow the order you give the columns if you give SORT by A B C that order will be taken if you give B A C then that order will be followed.

SO thats why you see that result.

Regards,

Sesh

[Former Member]

are you sure ? because it gives me

4 | 9 | 10

8 | 3 | 7

9 | 2 | 11

like this and it is the correct one.

regards

shiba dutta

[Former Member]

Hi,

check this code,

REPORT ZEX31 .

data : begin of itab occurs 0,

f1 type i,

f2 type i,

f3 type i,

end of itab.

itab-f1 = 9 .

itab-f2 = 2.

itab-f3 = 11 .

append itab.

clear itab.

itab-f1 = 4 .

itab-f2 = 9.

itab-f3 = 10 .

append itab.

clear itab.

itab-f1 = 8 .

itab-f2 = 3.

itab-f3 = 7 .

append itab.

clear itab.

loop at itab.

write : / itab-f1 , itab-f2 , itab-f3.

endloop.

sort itab by f1 f2 f3.

skip 2.

loop at itab.

write : / itab-f1 , itab-f2 , itab-f3.

endloop.

sorting will be based on the order u give,

if u give order f1 f2 f3 then first f1 will be checked and sorted in the order of it.

o/p will be

4 9 10

8 3 7

9 2 11

[Former Member]

Thank you very much for this great explanation and now it's working.