pass a table to the changing parameter

[Former Member]

This below shown code doesn't work because I get the message "p_ttest is not an internal table"

How can I get it working ?

TYPES: BEGIN OF tty_test,
       name(10) type c,
       zahl      type i,
       END OF tty_test.

data  ttest type table of tty_test.

perform training changing ttest .

write: ''.


FORM training changing p_ttest.
data xyz type tty_test.
xyz-name = 'John'.
xyz-zahl = '23'.
append xyz TO p_ttest.
ENDFORM.                    " 

[Former Member]

U need to declare some syntax for p_ttest.

See code below...

TYPES: BEGIN OF tty_test,

name(10) type c,

zahl type i,

END OF tty_test.

data ttest type table of tty_test.

perform training changing ttest .

write: ''.

FORM training changing p_ttest like ttest.

data xyz type tty_test.

xyz-name = 'John'.

xyz-zahl = '23'.

append xyz TO p_ttest.

ENDFORM.

[Former Member]

Hi,

change p_ttest to ttest.its working fine.

regards

[Former Member]

TYPES: BEGIN OF tty_test,

name(10) type c,

zahl type i,

END OF tty_test.

data ttest type standard table of tty_test.

perform training changing ttest .

write: ''.

FORM training changing p_ttest type standard table of tty_test.

data xyz type tty_test.

xyz-name = 'John'.

xyz-zahl = '23'.

append xyz TO p_ttest.

ENDFORM. "

Edited by: kartik tarla on Dec 4, 2008 3:17 PM

[Former Member]

Hi,

If u want to pass an internal table, then instead of the changing clause, use tables claues.

Regards,

Ajay

[Former Member]

hi,

use FORM training changing p_ttest type tty_test.

data xyz type tty_test.

xyz-name = 'John'.

xyz-zahl = '23'.

append xyz TO p_ttest.

ENDFORM.

regards,

Srilatha

[Former Member]

Hi,

Just a small change in your code.try this:

TYPES: BEGIN OF tty_test,

name(10) type c,

zahl type i,

END OF tty_test.

data:p_ ttest type table of tty_test.

perform training changing p_ttest .

write: ''.

FORM training changing p_ttest.

data xyz type tty_test.

xyz-name = 'John'.

xyz-zahl = '23'.

append xyz TO p_ttest.

ENDFORM. "

The error came because you have not made the internal table p_ttest.

after making the internal table only you can append the work area to intrnal table.

Hope it helps.

Rahul

Edited by: Rahul Kumar Sinha on Dec 4, 2008 10:50 AM

[Former Member]

U need to declare some syntax for p_ttest.

See code below...

TYPES: BEGIN OF tty_test,

name(10) type c,

zahl type i,

END OF tty_test.

data ttest type table of tty_test.

perform training changing ttest .

write: ''.

FORM training changing p_ttest like ttest.

data xyz type tty_test.

xyz-name = 'John'.

xyz-zahl = '23'.

append xyz TO p_ttest.

ENDFORM.

[Former Member]

PARAMETERS: p_carr TYPE sflight-carrid,

p_conn TYPE sflight-connid.

DATA sflight_tab TYPE STANDARD TABLE OF sflight.

PERFORM select_sflight TABLES sflight_tab

USING p_carr p_conn.

FORM select_sflight TABLES flight_tab LIKE sflight_tab

USING f_carr TYPE sflight-carrid

f_conn TYPE sflight-connid.

SELECT *

FROM sflight

INTO TABLE flight_tab

WHERE carrid = f_carr AND

connid = f_conn.

ENDFORM.

[Former Member]

TYPES: BEGIN OF tty_test,
       name(10) type c,
       zahl      type i,
       END OF tty_test.
 
data  ttest type table of tty_test.
 
perform training changing ttest[] .
 
write: ''.
 
 
FORM training changing p_ttest.
data : temp type table of tty_test.
data xyz type tty_test.
temp[] = p_ttest.
xyz-name = 'John'.
xyz-zahl = '23'.
append xyz TO temp.
p_ttest = temp[].
ENDFORM.                    "

[tarangini_katta]

hello erdem,

write lik ethis

TYPES: BEGIN OF tty_test,

name(10) type c,

zahl type i,

END OF tty_test.

data ttest type table of tty_test.

perform training changing ttest .

write: ''.

FORM training changing p_ttest type table .

data xyz type tty_test.

xyz-name = 'John'.

xyz-zahl = '23'.

append xyz TO p_ttest.

ENDFORM.

[Former Member]

Hi

TYPES: BEGIN OF tty_test,
       name(10) type c,
       zahl      type i,
       END OF tty_test.

data  ttest type table of tty_test.

perform training tables ttest .

write: ''.


FORM training tables p_ttest.
data xyz type tty_test.
xyz-name = 'John'.
xyz-zahl = '23'.
append xyz TO p_ttest.
ENDFORM.

Thanks.

Chitrali

[i048168]

Hi,

Try this,

FORM training changing p_ttest like ttest.

Regards,

Vadivelan B

[Former Member]

Hi erdem,

u haven't defin p_ttest anywhere in your code declare it like ttest in changing. because u already defined that ttest type table of tty_test.

it will work fine.

regards

Saurabh

[Former Member]

@kartik tarla your sample doesnt work

@Jansi Dorai your sample doesnt work

@Ajay Abhyankar this is obselete

@Rahul thank you but it is very circuitous

@ Ramesh has solved this problem finally