Padded by spaces

[Former Member]

Hello Experts ,

I have to pad a character field by spaces.

Eg : var1(5) type c.

Var1 can have value 'ab' or 'abc' etc...

Now if value is 'ab' , i should pad it with 3 spaces as ' ab'

and if value is 'abc' i should pad with 2 spaces as ' abc'.

So depending on value of var1 , it should be padded with spaces .

Conversion Exit is useful only Numeric fields.Please suggest a solution for char field.

Thanks.

[former_member156446]

Hi hope this helps:

DATA: var1(5) TYPE c VALUE 'AB'.
DATA:lv_len TYPE i, count TYPE i, lv_temp TYPE i.

DESCRIBE FIELD var1 LENGTH lv_len IN CHARACTER MODE.
count = STRLEN( var1 ).
lv_temp = lv_len - count.
DO lv_temp TIMES.
  CONCATENATE space var1 INTO var1.
ENDDO.

[Former Member]

this works...

data: testf(5) type c value 'ABC'.

start-of-selection.
  write: / '12345'.
  write: / testf.
* this works
  write testf to testf right-justified.
  write: / testf.

[Former Member]

Hi,

calculate the length of the value and then according to the length to decide how many spaces you should add.

Thanks.

Regards,

Chris Gu

Edited by: Gu Chris on Nov 11, 2008 4:09 AM

[Former Member]

Hi,

All character type variables/fields are left justified by default, so if you want to add padding to the beginning of a variable, just use the write statement in addition with the right-justified.

example-

data var1(5) type c value 'ab'.

write var.

this would give you and output

ab (left justified without and padding) but instead use the following

write var right-justified.

this would give you an output

ab.

that 3 spaces before writing value of the variable amounting to the total of 5 spaces.

Hope this will help you in solving your query.

Thanka and Regards,

Sachin Dargan