issue in select option values..

[Former Member]

hey,

i have a select option, s_kunnr. User enters a value for s_kunnr-high, but it is not taken into account in the select statement !!

my code is

read table i_dyn_fields index 4.

if not i_dyn_fields-FIELDVALUE is initial.

wa_KUNNR-HIGH = i_dyn_fields-FIELDVALUE.

CALL FUNCTION 'CONVERSION_EXIT_ALPHA_INPUT'

EXPORTING

input = wa_KUNNR-high

IMPORTING

OUTPUT = wa_KUNNR-high.

wa_KUNNR-sign = 'I'.

if NOT WA_KUNNR-LOW is initial.

wa_KUNNR-option = 'BT'.

else.

wa_KUNNR-option = 'EQ'.

endif.

append wa_KUNNR to s_KUNNR.

clear wa_KUNNR.

ENDIF.

what is the issue ??

thks

[Former Member]

wa_kunnr-low = somekunnr. " i hope it is there

read table i_dyn_fields index 4.
if not i_dyn_fields-FIELDVALUE is initial.
wa_KUNNR-HIGH = i_dyn_fields-FIELDVALUE.
CALL FUNCTION 'CONVERSION_EXIT_ALPHA_INPUT'
EXPORTING
input = wa_KUNNR-high
IMPORTING
OUTPUT = wa_KUNNR-high.
wa_KUNNR-sign = 'I'.

if NOT WA_KUNNR-LOW is initial.
wa_KUNNR-option = 'BT'.
else.
wa_KUNNR-option = 'EQ'.

endif.
append wa_KUNNR to s_KUNNR.
clear wa_KUNNR.
ENDIF.

[Former Member]

No Vijay. is there not a possibility that user does not enter any value for s_kunnr-low but directly enters for s_kunnr-high ?? should not SAP then take it as EQ according to my logic ??

[Former Member]

if that is the case you have to provide that as LOW and option = 'EQ'.

if kunnr-low is initial.

kunnr-low = kunnr-high.

kunnr-option = 'EQ'.

endif.

but you still want ' ' to kunnr what ever you enter then you can go ahead with that..

[Former Member]

Try this,

Append S_KUNNR directly instead of using WA.

E.g.:

S_KUNNR-SIGN = 'i"

S_KUNNR-OPTION = 'BT'

S_KUNNR-LOW =

S_KUNNR-HIHG =

Thanks,

SKJ

[Former Member]

u should build your logic in a way that u first populate low and then high part of the selection option. Without populating low if u populate high value then it will give u error. So I think u should first populate low and then high and based on it decides value for option field like:

if NOT WA_KUNNR-high is initial.

wa_KUNNR-option = 'BT'.

else.

wa_KUNNR-option = 'EQ'.

endif.

Pl. check ur code again..

[ian_maxwell2]

On ranges:

- BT - Uses Low and High

- EQ - Uses Low

This would mean from looking at your code that in the case where EQ is used it is actaully looking for a record where Kunnr is blank instead of the value that you put in High.

Just got to switch a couple of things around

~Ian

[Former Member]

if NOT WA_KUNNR-LOW is initial.
wa_KUNNR-option = 'BT'.
else.
wa_KUNNR-option = 'EQ'.
wa_kunnr-low = wa_kunnr-high. <-=== add this your low is space,but you are using EQ 
endif.
append wa_KUNNR to s_KUNNR.
clear wa_KUNNR.
ENDIF.

[Former Member]

Instead of the logic you have written, you can write much simpler logic.

LOOP AT s_kunnr INTO s_kunnr.

CALL FUNCTION 'CONVERSION_EXIT_ALPHA_INPUT'

EXPORTING

input = s_KUNNR-LOW

IMPORTING

OUTPUT = s_KUNNR-LOW.

CALL FUNCTION 'CONVERSION_EXIT_ALPHA_INPUT'

EXPORTING

input = s_KUNNR-high

IMPORTING

OUTPUT = s_KUNNR-high.

MODIFY s_kunnr FROM s_kunnr.

ENDLOOP.

and you are done... AS per your logic it's correct but the only mistake is you are appending a new row in s_KUNNR and you are not passing the value in s_kunnr-sign. so that's why it is not fetching anything.. try passing 'BT' into s_kunnr-sign and that will also work.

Rewards point if it is useful.

Thanks,

Navneet