give out variable as string on the screen

[Former Member]

hi all

i have define a variable and assign a value. Now i want show the variable as string in screen.

Example:

data lf_vab type i.

lf_vab = 1.

Output is

lf_vab = 1.

I know, i have might define LF_VAB as a constant but i wan't.

Thx abap_begin

[Former Member]

yes, i know, i can definition as string, look this problem

 data lf_vab1 type i .
 data lf_va type string value 'LF_VAB1'.

 lf_vab1 = 3
WRITE:  lf_va, ' = ' , lf_vab1.

Now the output is

LF_VAB1= 3

When i change later the variable name, then the output isn't right.

Example

 data lf_vab type i .
 data lf_va type string value 'LF_VAB1'.

 lf_vab1 = 3
WRITE:  lf_va, ' = ' , lf_vab1. "Now is wrong, because the Variable LF_VAB1 isn't exist

What i want is, get the variable name as string. Is for dynamic programing.....

Thx abap_begin

Edited by: abap_begin on May 6, 2010 10:41 AM

[Former Member]

Define it as String ..Thats It.

[Former Member]

Tried quite hard to understand the question. But couldn't

[Former Member]

yes, i know, i can definition as string, look this problem

 data lf_vab1 type i .
 data lf_va type string value 'LF_VAB1'.

 lf_vab1 = 3
WRITE:  lf_va, ' = ' , lf_vab1.

Now the output is

LF_VAB1= 3

When i change later the variable name, then the output isn't right.

Example

 data lf_vab type i .
 data lf_va type string value 'LF_VAB1'.

 lf_vab1 = 3
WRITE:  lf_va, ' = ' , lf_vab1. "Now is wrong, because the Variable LF_VAB1 isn't exist

What i want is, get the variable name as string. Is for dynamic programing.....

Thx abap_begin

Edited by: abap_begin on May 6, 2010 10:41 AM

[Former Member]

data lf_vab type i .
 data lf_va type string value 'LF_VAB1'.
 
 lf_vab = 3
WRITE:  lf_va, ' = ' , lf_vab. 

if if you change the varible name ten you have to change in all the place.Please check your codings.

you are declared lf_vab but used as lf_vab1