Functionality of MOD operator with packed varialbles.

[aaruljothi]

Hi,

I have given a code bit below. Please explain me how day_p

is calculated.

data: DATE LIKE SCAL-DATE.

DATA: DAY_P TYPE P.

data: n type i.

n = 7.

date = sy-datum.

day_p = DATE MOD n.

write: / n , date , day_p.

Results: for

n = 7 Date: 12.09.2005 day_p: 2 how?

n = 3 Date: 12.09.2005 day_p: 1 how?

n = 5 Date: 12.09.2005 day_p: 2 how?

[aaruljothi]

Hi,

I have given a code bit below. Please explain me how day_p

is calculated.

data: DATE LIKE SCAL-DATE.

DATA: DAY_P TYPE P.

data: n type i.

n = 7.

date = sy-datum.

day_p = DATE MOD n.

write: / n , date , day_p.

Results: for

n = 7 Date: 12.09.2005 day_p: 2 how?

n = 3 Date: 12.09.2005 day_p: 1 how?

n = 5 Date: 12.09.2005 day_p: 2 how?

[RichHeilman]

MOD is for remainders.

F1 help.

<i>

DIV and MOD

The integer division operators DIV and MOD are defined as follows:

ndiv = n1 DIV n2

nmod = n1 MOD n2

so that:

n1 = ndiv * n2 + nmod

ndiv is an integer

0 <= nmod < |n2|

If n2 = 1 and n1 <> 0, a runtime error occurs.

Example

DATA: D1 TYPE I, D2 TYPE I, D3 TYPE I, D4 TYPE I,

M1 TYPE P DECIMALS 1, M2 TYPE P DECIMALS 1,

M3 TYPE P DECIMALS 1, M4 TYPE P DECIMALS 1,

PF1 TYPE F VALUE '+7.3',

PF2 TYPE F VALUE '+2.4',

NF1 TYPE F VALUE '-7.3',

NF2 TYPE F VALUE '-2.4'.

D1 = PF1 DIV PF2. M1 = PF1 MOD PF2.

D2 = NF1 DIV PF2. M2 = NF1 MOD PF2.

D3 = PF1 DIV NF2. M3 = PF1 MOD NF2.

D4 = NF1 DIV NF2. M4 = NF1 MOD NF2.

</i>

Regards,

Rich Heilman

[RichHeilman]

Please remember to award points for helpful answers. Thanks.

Regards,

Rich Heilman

[Former Member]

Can you please tell what you want to achieve with this code?

[guillaume-hrc]

Hi,

Let's do some Maths !

20050912 / 7 = 284416

So, the remainder (day_p) should be 0 and not 2 !!

It tried this code :

DATA: DATE LIKE SCAL-DATE.
DATA: DAY_P(8) TYPE p.
DATA: DAY_P1(8) TYPE p.

DATA : date_bis(8) TYPE n.
data: n type i.
n = 7.

date = sy-datum.
day_p = DATE MOD n.

date_bis = sy-datum.
day_p1 = DATE_bis MOD n.

write: / n , date, day_p.
write: / n , date_bis, day_p1.

and day_p1 is giving the good result.

For what I have tested, it seems that everything behaves as if the date variable has the value 12092005 (although we know that it's 20050912 in its internal format)

Strange behaviour !

[Former Member]

I was looking at this too and got the same result. I think it's worthwhile remembering that although we express dates as numbers for convenience, they're not really numbers (at least not rational numbers). You can add and subtract them, but multiplication and division make no sense. Even when adding and subtracting, you can get different answers depending on the order you perform the operations.

Rob

[Former Member]

Hi,

Before a math operation is performed with a date value, SAP converts the date to an integer. The integer value is equal to the count of days from 00.00.0000. The integer vale of 12.09.2005 is 732202. After the coversion, the math operation is performed.

732202 (12.09.2005) mod 7 = 2

This is the whole logic.

Svetlin

[Former Member]

You made me think Svetlin. Thanks for that insight. Yes, SAP actually treats the date as an integer number which is equal to the number of days since the begining(2nd January 0001 = 1). I did a quick math and yes 365 days times 2005 years is 731825. Add to that the corrections and leap year additional days etc, we have 732202 for the date 12.09.2005.

Srinivas

[Former Member]

Arul,

If answered, please reward and close.

Thanks,

Srinivas