Find Substring + 2 characters in a string

[Former Member]

I have the following string: 1.0000000000000000E+01

I need to find subtring E+01 and delete it from the string.

problem is thet 01 can be anything and changes.

I need an expression that will find a subtring starting E+ and two characters that come after ie 01

<removed_by_moderator>

Edited by: Julius Bussche on Sep 15, 2009 10:31 AM

[Former Member]

Hi,

Hope this code will give you an idea of how to do this.

DATA: str TYPE string VALUE '1.00000000000E+02',
      result_tab TYPE match_result.

FIND 'E+' IN str RESULTS result_tab.

WRITE:/ str+result_tab-offset.

Regards,

Naga Sai Swapna

[former_member188827]

split string at 'E' into ch1 ch2.

ch1 is the string that doesnt contain your desired substring.

[Former Member]

Hi,

Here is the code acc to the requirement...

data:
w_str(30) type c value '1.0000000000000000E+01',
w_off type i.
search w_str for 'E+'.
write: sy-fdpos.
w_off = sy-fdpos.
w_str+w_off(4) = space.
write: w_str.

Regards,

Mdi.Deeba

[Former Member]

Hi,

Try the below code;

Data : str(100) type C value '1.0000000000000000E+01'.
Data : len type i.
len = strlen( str ) - 4.
str = str+0(len).

This will solve the problem.

>

> Will award points pls help.

Do not offer points its against [Forum Rules|http://wiki.sdn.sap.com/wiki/x/FgQ].

Regards

Karthik D

[Former Member]

Hi,

Try this,

data: w_var1(10) type C value '100E+01',

var1(10) type c,

var2(10) type c.

if w_var1 CS 'E+'.

Split w_var1 at 'E+' into var1 var2.

Endif.

Write: var1, var2.

[Former Member]

Hi,

Try following code

DATA : TEMP TYPE STRING,

CHAR_1(20) TYPE C,

CHAR_2(10) TYPE C.

TEMP = '1.0000000000000000E+01'.

SPLIT TEMP AT 'E+' INTO CHAR_1 CHAR_2.

IF CHAR_2 = '01'.

char_1 contains value you need, you can move this value to the desired internal table.

ENDIF.

Hope this helps.

Edited By Tejaswini Khante

[Former Member]

Hi,

Hope this code will give you an idea of how to do this.

DATA: str TYPE string VALUE '1.00000000000E+02',
      result_tab TYPE match_result.

FIND 'E+' IN str RESULTS result_tab.

WRITE:/ str+result_tab-offset.

Regards,

Naga Sai Swapna

[rainer_hbenthal]

Strange requirement....

1.0000000E+01 is 10

1.0000000E+02 is 100

After deleting the exponent both values are 1.....

If it is to convert a stringrepresantion of a floating number to a number there are better solutions...

[Former Member]

Hi Maksims Jegorovcevs,

Use below code... it will solve your problem... Use offset condence etc while solving this kind of requirement..

PARAMETERS : P_STR(30) TYPE C DEFAULT '1.000000000E+010000000'.

DATA: L_OFFSET TYPE I.

WRITE: / 'INPUT  : ' , P_STR.

SEARCH P_STR FOR 'E+'.

L_OFFSET = SY-FDPOS.

P_STR+L_OFFSET(4) = ''.

CONDENSE P_STR NO-GAPS.

WRITE: / 'OUTPUT : ', P_STR.

Hope it will solve your problem..

Thanks & Regards

ilesh 24x7

ilesh Nandaniya