digits

[Former Member]

hi i have a 6 char field .

in that i have to check each character is a char or numeric .

pls help me

[Former Member]

USING SEARCH SYNTAX U CAN EASY FIND EASYLY DO.

[Former Member]

Hi

declare 2 variables:

data: char(26) type c value 'ABCDEFGHIJKLMNOPQRSTUVWXYZ',

num(9) type value '1234567890',

str(6) type c value 'ABF123'.

now use the string comparison paramters like CS,CO,CN etc and check

if str CS char or Str CO num.

.............

endif.

Regards

Anji

[JozsefSzikszai]

hi Chaaya,

IF string CO '0123456789'.

==> it is number

ELSE.

==> it is something else (i. e. not only numbers)

ELSE.

if you have to do it character by character, than you can do in a DO-ENDDO.

hope thishelps

ec

[Former Member]

do.

try

if string(sy-index) IN '0123456789'.

write: / string(sy-index) ' is a number'.

else

write: / string(sy-index) ' is not a number'.

catch CX_root.

exit.

endtry.

enddo.

*reward if solved*

[Former Member]

data: cnt type i value 0.

do 6 times.

if str+cnt(1) CO '0123456789'.

message i000.

endif.

enddo.

Hope dis helps..

Reward if it does

[Former Member]

Hi,

Try like this:

data: v_string(15) type c value 'BHASKAR2006'.

data : str(10) type c.

str = v_string+0(5).

write str.

if str CA sy-abcde.

write 'Characters'.

else.

write 'Numerics'.

endif.

Regards,

Bhaskar