Defining table in the interface of function

[Former Member]

Hi @ll,

I have created an structure XX with many fields. Under the "table"-tab in my function ZZ I need to define a table YY referring to my structure XX to fill some rows and handing over it to an external function TT.

Now when I try to check my function ZZ and activate it I get the syntax error "structure XX" must be a flat structure. You cannot useinternal tables, strings, references, or structures as components.

Can anybody help.

Thanks

Kam

[Sm1tje]

Are you using TYPE or LIKE?

Edited by: Micky Oestreich on Apr 29, 2008 6:42 PM

[Former Member]

no mater LIKE or TYPE I get the same message

[Former Member]

Hello,

Please check if the structure don't contains tables as fields (deep structure) or reference variables.

Regards,