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date problem

Former Member
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903

pa0028-exdat = '20080401'.

Wish to get month.

month = ' 04'.

1 ACCEPTED SOLUTION
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Former Member
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879

Hi,

Use the following code.

pa0028-exdat = '20080401'.

month = pa0028-exdat+4(2).

REWARD IF USEFUL

8 REPLIES 8
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Former Member
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879

Hi,

will u be a little bit clear abt ur doubt?

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Former Member
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879

Hi,

Try this FM.

HR_IN_GET_DATE_COMPONENTS

Regards,

Ramya

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Former Member
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880

Hi,

Use the following code.

pa0028-exdat = '20080401'.

month = pa0028-exdat+4(2).

REWARD IF USEFUL

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Former Member
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879

Hi abhut,


write pa0028-exdat+4(2).

The above means

LEAVE 4 characters &

TAKE 2 characters

regards,

amit m.

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Former Member
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879

write:/ pa0028-exdat+4(2)

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prasanth_kasturi
Active Contributor
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879

hi,

month = pa0028-exdat+4(2).

regards

prasanth

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Former Member
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879

data: v_date type d ,

mon(2) type c .

pa0028-exdat = '20080401'.

v_date = pa0028-exdat .

mon = v_date+4(2) .

write:/ mon .

regards,

venkat.

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Former Member
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879

Hi ABHUT,

Use string manupulation for retrieving the month by parsing the date string

Example :

Data : l_date type D,

l_month(02).

l_date = '20080401' .

l_month = l_date+4(2).

Hope this helps.

Thanks,

Greetson

Edited by: Greetson Shunmugasundaram on Apr 23, 2008 2:28 PM