‎2007 Mar 22 4:43 PM
Hi,
I am getting wa_input-invdt as 060719, I want this to be as 07/19/2006. Can you please help me to convert this.
Thanks
Veni.
‎2007 Mar 22 4:48 PM
Hi,
Please try this FM CONVERT_DATE_TO_INTERN_FORMAT.
Regards,
Ferry Lianto
‎2007 Mar 22 4:48 PM
Hi!
CONCATENATE wa_input-invdt2(2) '/' wa_input-invdt4(2) '/20' wa_input-invdt(2) INTO lv_datum.
Regards
Tamá
‎2007 Mar 22 4:51 PM
check this FM -CONVERT_DATE_FORMAT
it will do the same.
Regards,
Amit
‎2007 Mar 22 5:01 PM
‎2007 Mar 22 5:17 PM
Hi Veni,
DATA V_DATE(10).
DATA V_YEAR(4).
CONCATENATE '20' WA_INPUT-INVDT+0(2) INTO V_YEAR.
CONCATENATE WA_INPUT-INVDT2(2) WA_INPUT-INVDT4(2) V_YEAR INTO V_DATE SEPARATED BY '/'.
WRITE V_DATE.
Thanks,
Vinay