Contains String

[Former Member]

I have a problem where value 1 contains 'ABCDEDFEGH' and valu2 contanis 'ABCDE'. I am using the CS operator but its not working.

IF value1 CS value2.

THEN do processing

I am actually looking for a string BESPAK in a string containg 'BESPAK PLC / KINGS' - but it doesn't work see the below exmaples

lv_len = STRLEN( ls_cust-customer ).

lv_string = ls_cust-customer(lv_len).

lv_string2 = gs_cust-customer.

THIS FAILS?????

IF lv_string2 CS lv_string.

gs_cust-customer = ls_cust-customer.

COLLECT gs_cust INTO gt_cust.

ENDIF.

THIS WORKS

IF 'BESPAK PLC' CS 'BESPAK'..

WRITE: 'Yeah'.

ENDIF.

THIS WORKS

IF gs_cust-customer CS 'BESPAK'.

COLLECT gs_cust INTO gt_cust.

ENDIF.

Edited by: showthousand on Mar 16, 2011 6:23 PM

[Former Member]

Hi

Please check in debugg the values of lv_string2 and lv_string.

You must have the values lv_string2 = 'BESPAK' and lv_string = 'BESPAK PLC'. That means it is working fine since lv_string2 does not have whole string 'BESPAK PLC' .

Reverse your condition it will work.

Regards

Sachin

Edited by: sachin G patil on Mar 17, 2011 8:49 AM

[Former Member]

change your statement like this, it will definitely work.

IF lv_string CS lv_string2 .

gs_cust-customer = ls_cust-customer.

COLLECT gs_cust INTO gt_cust.

ENDIF.

[Former Member]

Hi

Reverse your condition.

because lv_string2 is smaller than lv_string.

hence lv_string2 is a part of lv_string.

we need to check whether lv_string contains the values similar to lv_string2.

so your statement should be like:

if lv_string CS lv_string2.

do processing.

endif.

Thanks

LG

[former_member183804]

Are your variables typed the same or is one STRING and the other C<nn>? This can cause subtle errors especially with the logic of trailing blanks.

[Clemenss]

Hi showthousand,

format code as code, give us the values you use and explaion what works and what does not work.

Thank you.

Regards,

Clemens