Amstrong number

[Former Member]

Hi,

How to write a program.

1. Accept a number and display whethere it is a amstrong number or not.

Thanks

[Former Member]

Hi Rams

Check the below code snippet.

parameters : num type numc3.

data : sum type i.

sum = num(1) ** 3 + num+1(1) ** 3 + num+2(1) ** 1.

if num = sum.

write : ' Armstrong Number'.

else.

write : 'Not a good one!'.

endif.

Reward points if helpful!!

~Ranganath

[Former Member]

Hi Rams

Just a little mistake in the previous one.

Check this.

Check the below code snippet.

parameters : num type numc3.

data : sum type i.

sum = num(1) ** 3 + num+1(1) ** 3 + num+2(1) ** 3.

if num = sum.

write : ' Armstrong Number'.

else.

write : 'Not a good one!'.

endif.

Reward points if helpful!!

~Ranganath

[Former Member]

*34) Write a program to find the sum & product of the first “N”

*Armstrong numbers. The user should enter a value for “N”. (Word of

*caution: See that the user should not enter a value for “N” which is

*more than 5).

PARAMETERS:

P_INPUT TYPE I.

DATA:

W_COUNT TYPE I,

W_INTVALUE TYPE I,

W_TEMP TYPE I,

W_QUO TYPE I,

W_RESULT(10) TYPE N VALUE 0,

W_PRODUCT(10) TYPE N VALUE 1,

W_SUM(10) TYPE N VALUE 0.

IF P_INPUT GT 5.

WRITE:

'Donot Enter Number > 5'(003).

ELSE.

WHILE W_COUNT LE P_INPUT.

ADD 1 TO W_INTVALUE.

W_TEMP = W_INTVALUE.

W_RESULT = 0.

WHILE W_TEMP > 0.

W_QUO = W_TEMP MOD 10.

W_RESULT = W_RESULT + W_QUO * W_QUO * W_QUO.

W_TEMP = W_TEMP DIV 10.

ENDWHILE.

IF W_RESULT = W_INTVALUE.

W_COUNT = W_COUNT + 1.

W_SUM = W_SUM + W_RESULT.

W_PRODUCT = W_PRODUCT * W_RESULT.

ENDIF.

W_INTVALUE = W_INTVALUE + 1.

ENDWHILE.

ENDIF.

WRITE:

/ 'Sum of the Armstrong Numbers '(001),W_SUM,

/ 'Product of the Armstrong Numbers '(002),W_PRODUCT.

Regards,

Pavan

[Former Member]

Hi Ram,

parameters : NO(5) type N

data : sum type i,

v_length type i,

v_number type i,

c_three type i value '3'.

v_length = length( NO ).

do v_length times.

v_number = v_length+sy-index(1).

v_number = v_numbr ** c_three.

sum = sum + v_number.

clear v_number.

enddo.

if NO = sum.

write : ' Armstrong Number'.

else.

write : 'Not a good one!'.

endif.

Thanks,

Vinay

[Former Member]

Hi,

check out the below program it might help you

REPORT ZVENKI.

parameters : enter type numc3.

• enter is the value which you enter at run time.

data : sum type i.

• sum is an variable which will store the result of your calculation.

sum = enter(1) ** 3 + enter+1(1) ** 3 + enter+2(1) ** 3.

• 111 + 555 + 333 = 153.

• 153 = 153.

if enter = sum.

• if entered number is evaul to calculated number then its an armstrong number.

write : ' Armstrong Number'.

• 153 is an armstrong number

else.

write : 'Not an armstrong number'.

*othe number is not an armstrong number

endif.

**********please reward points if the information is helpful to you***************

[former_member189059]

Program to find all amstron numbers

REPORT  z_amstron.

DATA : num TYPE numc4.
DATA : COUNT TYPE i VALUE 0.
DATA : sum TYPE i.

DO 10000 TIMES.
  num = COUNT.
  PERFORM get_ams.
  COUNT = COUNT + 1.
ENDDO.

*&---------------------------------------------------------------------*
*&      Form  get_ams
*&---------------------------------------------------------------------*
*       text
*----------------------------------------------------------------------*
FORM get_ams.
  sum = num(1) ** 3 + num+1(1) ** 3 + num+2(1) ** 3 + num+3(1) ** 3.
  IF num = sum.
    WRITE : / num , ' is an Amstron number'.
  ENDIF.
ENDFORM.                    "get_ams

[Former Member]

hi,

hope it helps u.

parameter n type i.

data : s type i,

rem type i,

d type i .

s = n.

while n gt 0.

rem = n mod 10.

d = d + rem * rem * rem.

n = ( n ) div 10.

endwhile.

if s eq d.

write 'armstrong'.

else.

write 'not armstrong'.

endif.

please reward points.