on ‎2006 Feb 09 12:06 PM
Hi ,
I have table in the following format
USERID LDATE LTIME
0000000001 2006.02.09 172005
0000000001 2006.02.09 172055
0000000001 2006.02.09 172224
I need to get the users earlier logon date & time(Only single record). I this case I have to pick up the third record ie 0000000001 2006.02.09 172224
For getting this record how we can use SELECT Single or SELECT UPTO 1 Rows.
My WHERE condition will be like this,
where userid eq lv_userid and
ldate le sy-datum and
ltime lt sy-uzeit.
I Dont want to read all the record by SELECT ENDSELECT and then validate to pickup the latest one ( Since this table will contain huge number of records).
It would be great if anyone higlight a optimized select statement.
BR,
Raj
Request clarification before answering.
HI
I would prefer sort the table based on the logon time in desending which will return the last logon time from which you can use select single which will retrieve the data required.
regards
kishore
reward if helpful
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Hi,
When it is returning a single record selectsingle is preferred to select . The syntax of using selectsingle is similar to select statement except it will not have endselect.Tell me if you are not able to do can give you more information.
Regards,
Sudheer.
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Hi raja,
1. U may have to use something like this.
SELECT EBELN MIN( AEDAT ) FROM EKKO
INTO CORRESPONDING FIELDS OF TABLE EKKO
GROUP BY EBELN AEDAT.
in your case.
-
SELECT USERID MIN( LDATE ) MIN( LTIME )
FROM DBTABLE
GROUP BY USERID.
3. U can insert your where conditions .
regards,
amit m.
Message was edited by: Amit Mittal
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Hi Raja,
You can use sort statment by Comparing the log on time field. Then you delete the other unwanted entries. So u will have single record with earlier log on time.
Thanks,
Srinivas.
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