validate that a string is composed from a defined character set

[Former Member]

Hi experts,

I need to validate that a string enetered as parameter is composed of the following character set :

26 alphabets (both in capital or lower case), a “’” (like O’Brien), a blank between characters like (Mc Donald). So the total valid characters on any of these fields will be 54.

could You provide with an efficient code ?

Plz Help....

rewards gauranteed........

[Former Member]

Hi,

Use variable CA { a,b,c}

Reward points

[Former Member]

Hi,

Please find the folowing code.

Use the comparing operator 'CO'. On right side you can write all your 54 possible characters.

data : str1 type string value 'eCA d'.

if str1 Co 'ABCdefghijklmnopqrstuvwx yz*'.

break-point.

endif.

reward if it helps.

regards,

mahantesh

[Former Member]

Hi,

Check the below code.

data: var(52) type c Value 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'.

data: v1(14) type c value 'welcome to SDN'.

data: v2 type i.

data: v3 type i.

v3 = 0.

v2 = STRLEN( v1 ).

do v2 times.

if v1+v3(1) = space .

write:/ 'test contains character space'.

elseif v1+v3(1) ca var.

write:/ 'test'.

elseif v1(v3) = '/'.

write:/ 'test contains character /'.

endif.

v3 = v3 + 1.

enddo.

Regards,

Shravan G.

[BGarcia]

Hello,

You can use regular expressions for validating the characters.

For example:

DATA: lv_string TYPE string VALUE 'My Name is O''Neill'.

DATA: lv_pattern TYPE string VALUE '[a-zA-Z| |'']+'.

DATA: lv_result TYPE boolean.

lv_result = CL_ABAP_MATCHER=>MATCHES( pattern = lv_pattern text = lv_string ).

If lv_result is X, it is OK. If is empty, then a invalid character is in the string.

Regards.