Type conversion from Chr10 to NUMC2

[Former Member]

Hello,

data:l_days(10) type c.

l_val(2) type n.

l_days = 5,00.

I want to to get output l_val = 5.

How to do this.

I tried this way

FIELD-SYMBOLS : <n1> type numc2.

ASSIGN l_z_days TO <n1> CASTING.

MOVE <n1> to l_z1_days.

But , Assign don't return any value .

Please advice

Thanks,

PK

Edited by: PK on Jan 22, 2008 9:56 AM

[Former Member]

Hello,

data:l_days(10) type c.

l_val(2) type n.

l_days = 5,00.

I want to to get output l_val = 5.

How to do this.

I tried this way

FIELD-SYMBOLS : <n1> type numc2.

ASSIGN l_z_days TO <n1> CASTING.

MOVE <n1> to l_z1_days.

But , Assign don't return any value .

Please advice

Thanks,

PK

Edited by: PK on Jan 22, 2008 9:56 AM

[Former Member]

Hi,

data:l_days(10) type c,

l_val1(2) type c,

l_dec type char10,

l_val(2) type n.

l_days = 5.00.

SPLIT l_days AT '.' INTO l_val1 l_dec.

l_val = l_val1.

Edited by: Ramesh Hirial on Jan 22, 2008 5:29 PM

[Former Member]

Hi PK,

Since I_Days is of type c seperated by comma, you can try like this

Declare two character variables A and B split i_Days into A and B.

then write A.

Regards,

DVNS

[Former Member]

How about doing it this way:

data:l_days(10) type c,
     l_val(2) type n.

l_days = '5,00'.

replace ',' with ' ' into l_days.
condense l_days no-gaps.
shift l_days left deleting leading space.

l_val = l_days(2).

Regards

Eswar

[Former Member]

@Eswar:

I guess, this would lead to L_VAL = 50, wouldn´t it?

[Former Member]

Hey Mike

Yes you are right, the returning value is 50 which was what he was expecting. The code i have provided was as per his post before editing.

Maybe new ideas make him to change the post and my reply doesnt make sense anymore.

Regards

Eswar