Subtracting two dates

[Former Member]

Hi all,

is there a Function Module for subtracting two dates.

i.e.

Date1 = 20060629

Date2 = 20060703

the answer is 4 days.

Thanks in advance.

[Former Member]

hi,

PARAMETER:p_date1 TYPE dats,
          p_date2 TYPE dats.
 
DATA:lv_diff TYPE i,
     lv_no_date type i.
 
 
CALL FUNCTION <b>'DAYS_BETWEEN_TWO_DATES'</b>
  EXPORTING
    i_datum_bis             = p_date1
    i_datum_von             = p_date2
  IMPORTING
    e_tage                  = lv_diff
  EXCEPTIONS
    days_method_not_defined = 1
    OTHERS                  = 2.
IF sy-subrc <> 0.
  WRITE:/ 'Error'.
ELSE.
  WRITE:/ lv_diff.
ENDIF.
 
if lv_diff < 0.
lv_diff = lv_diff * -1.
endif.
 
lv_no_date = lv_diff - 1.

Check this thread out

Reward it it helps,

Santosh

[Simha_]

Hi,

simply u can use ans = date2- date1.

It helps...

Cheers,

SImha.

[Former Member]

Hi ,

you can use this FM.

HR_HK_DIFF_BT_2_DATES

Regards,

Sumit.

[Former Member]

hi,

you can use the function module

HR_HK_DIFF_BT_2_DATES

Reward if helps.

Thanks,

krishnakuamr

[Former Member]

if u subtract directly 2 date variables to an integer variable it will give u the difference in days only.

example :

x = date1 - date2. where x is an interger.

[Former Member]

Hi,

Try this function module.

"HR_HK_DIFF_BT_2_DATES"

For this DATE1 should be greater that DATE2.

Check the following code...

DATA: lw_date1 TYPE p0001-begda,

lw_date2 TYPE p0001-begda,

lw_date TYPE p0347-scrdd.

lw_date1 = sy-datum.

lw_date2 = '12.12.2004'.

CALL FUNCTION 'HR_HK_DIFF_BT_2_DATES'

EXPORTING

date1 = lw_date1

date2 = lw_date2

OUTPUT_FORMAT = '02'

IMPORTING

days = lw_date.

Thanks and regards,

Bharat Kuamr Reddy.V

[Former Member]

Hi check the following ,

http://www.sapdb.org/7.4/htmhelp/d1/cc7498bb4111d2a97100a0c9449261/content.htm

Please reward for the same.