spaces in string

[Former Member]

Dear Gurus,

I have a string .

'My name is Roshan Lilaram Wadhwani'

I need to find the number of spaces used in this string.

Rather i need to segregate the string in two parts after a particular number of spaces.

Regards,

Roshan Lilaram.

[dev_parbutteea]

Hi,

try the folowing codes:

data :

varxx type string value 'Test',

len type i.

len = strlen( varxx ).

write: varxx, ' Lenght:', len.

len2 = len/2.

segregate the string in two parts like this:

move varxx(len2 ) to temp1.

move varxx+len2 to temp2.

[dev_parbutteea]

Please reward if this solves your problem,

Regards,

Sooness.

[Former Member]

hi

You can use the function module SWA_STRINGLENGTH_GET to find the number of spaces in the string.

for this you can call this function module twice.

first when you are not going to set the parameter CONDENSE_NO_GAPS.

and get the length of the string with spaces.

after that call the function module againg and set CONDENSE_NO_GAPS = X.

now the length of the string will be without spaces.

you can substract the two to get the number of spaces.

Reward if helpful.

Mohit

[Former Member]

TRY THIS

DATA : TEXT(50)  VALUE 'My name is Roshan Lilaram Wadhwani',
       LEN TYPE I,
       POS TYPE I,
       COUNTER TYPE I,
       V_CH,
       V_SPACE VALUE ' ',
       V_TXT(30),
       V_TXT2(20).

COMPUTE LEN = STRLEN( TEXT ).

DO LEN TIMES.
 V_CH = TEXT+POS(1).
 IF V_CH EQ SPACE.
  COUNTER = COUNTER + 1.
 ENDIF.

 IF COUNTER LT 3.
  CONCATENATE V_TXT V_CH INTO V_TXT.
 ELSE.
  CONCATENATE V_TXT2 V_CH INTO V_TXT2.
 ENDIF.
 POS = POS + 1.
ENDDO.

WRITE : / V_TXT.
WRITE : / V_TXT2.

REGARDS

SHIBA DUTTA

[Former Member]

i have used split command.

Thank you all very much.