spaces in a string

[Former Member]

Hello ,

MY requirement is to find how many spaces in a string ..is there any function module plz advise.

thanks.

[Former Member]

Hi!

Use the SEARCH command for this. In higher SAP versions (ECC6) you can use the FIND as well.

Regards

Tamá

[Former Member]

Hi!

Use the SEARCH command for this. In higher SAP versions (ECC6) you can use the FIND as well.

Regards

Tamá

[Former Member]

hello there ,

thanks for your reply. I am getting an runtime error saying endless loop..any help?

Thanks

[SuhaSaha]

Hello,

DATA: v_str TYPE string,
      v_len_ini TYPE i,
      v_len_fin TYPE i,
      v_spaces TYPE i.

v_str = `Welcome to SDN ABAP Forums `.
v_len_ini = STRLEN( v_str ).

WRITE / v_str.

CONDENSE v_str NO-GAPS.
v_len_fin = STRLEN( v_str ).

WRITE / v_str.

v_spaces = v_len_ini - v_len_fin.

IF v_spaces > 0.
  WRITE: / 'No of spaces:', 20 v_spaces.
ENDIF.

Does this solve your req ?

BR,

Suhas

[kesavadas_thekkillath]

Hey Suhas,

Thats Cool

[former_member217544]

Hi,

May be there are many ways. But one way is using split:

data: itab type table of string,
count type i.
split v_string at c_space into table itab.

describe table itab lines count.
count = count - 1.
Now count contains the number os spaces in the string.

@Keshav,

Sorry,ended up by posting same solution as I didnt checked your suggestion before posting

Regards,

Swarna Munukoti.

Edited by: Swarna Munukoti on Jan 29, 2010 12:26 PM

[rameshkumar_ramasamy2]

hi,

u can try this..

PARAMETER dat TYPE string.
DATA count TYPE i.

DATA: len TYPE i,
      var TYPE c.

len = strlen( dat ).


do len TIMES.
len = len - 1.
var  = dat+len(1).
if  var = ' '.
  count = count + 1.
ENDIF.
enddo.
WRITE / count.

[Former Member]

PARAMETER dat TYPE string.

Is STRING data type allowed?

Manas M.

[kesavadas_thekkillath]

You can check the f1 help of find and search.

But what comes to my mind now is

Split lv_string at space into table itab."make sure that the syntax is correct

describe table itab lines lv_lines.

lv_lines = lv_lines - 1.

write:'Spaces-',lv_lines.