Select with a dynamic value table

[Former Member]

Hello,

I have to tables t1 and t2. In the first table I have a field f1 which has the name of t2 as value.

How has to be the Select Statement

I tried

DATA: l_table TYPE CHAR5 .

Select v1 into l_table from t1

Select v2 into xx from (l_table).

But I get there allways an error and I could not find an starting point in seach for this problem.

Thank for any help

Regards

Henning

Edited by: Alvaro Tejada Galindo on Apr 10, 2008 5:15 PM

[Former Member]

Do like this

Select v1 into l_table from t1.
endselect.
Select v2 into xx from (l_table).
endselect.

[Former Member]

Hi,

the problem may be with select use select single.

or else give the error description.

DATA: l_table TYPE CHAR5 .

data:var(10).

Select SINGLE f1 into l_table from t1.

Select SINGLE f into var from (l_table)."here ensure that field F is there in table T2.

rgds,

bharat.

[ThomasZloch]

what is the exact error message?

is your table name really only 5 characters long (CHAR5)?

[Former Member]

Hello,

and thanks for the answer.

I have localized that it has something to do with the concatenate, so I post the original code (the tables have more than 5Char sorry for that).

If I set DATA: l_table Type CHAR20

If I am setting the value for the l_table it works fine so in my opinion it has something to do with the concatenate but the result of the concatenate is also fine i checked it wit se11 the result is exactly the tablename.

The error is:

Laufzeitfehler DBIF_RSQL_INVALID_RSQL

Ausnahme CX_SY_OPEN_SQL_DB

DATA: l_period TYPE char40.

DATA: l_table TYPE CHAR20.

break-point.

Select ODSNAME from rstsods into l_table

where

USEROBJ = '6DB_K5'.

ENDSELECT.

concatenate l_table '000' into l_table." I need this because the value of the table has not the 0

SELECT k850_periode

FROM (l_table)

INTO l_period.

ENDSELECT.

[ThomasZloch]

Hi Henning,

the "short" dump should give you more information somewhere about the actual problem: does the table you are accessing dynamically not exist, or does the column k850_periode not exist in that table, or could it be that k850_periode and l_period are defined differently?

Greetings

Thomas

[Former Member]

Hello,

I found my mistake the table name was not right. What a stupid mistake

But thanks again to all it was very helpfull

Henning