read table

[Former Member]

hi,

i want to read kunnr from my internal table where name1 = 'vicky' , land1 = 'india'. I want to use the read statement.

regards,

sunny

[Former Member]

Hi,

decalre an internal table and an explicit work area for that.

loop at it.

ReaD TABEL (INTERNAL TABLE NAME) INTO wa with key kunnr = 'VICKY' and land1 = 'INDIA'.

append wa.

modify itab from wa.

clear wa.

endloop.

write : wa-kunnr, wa-land1.

[Former Member]

Hi..

Read table internal_table into wa_itab

where name = 'VICKY' and land1 = 'INDIA'.

<REMOVED BY MODERATOR>

Regards.

Edited by: Alvaro Tejada Galindo on Apr 10, 2008 6:02 PM

[amit_khare]

Read itab into wa_itab with key name1 = 'vicky'

land1 = 'india'.

if sy-subrc = 0.

v_kunnar = 2a_itab-kunnr.

endif.

Regards,

Amit

[Sandeep_Panghal]

Hi,

Try this:

Read table it_kunnr into work area with key name = 'XYZ'

land1 = 'ABC'.

check sy-subrc.

<REMOVED BY MODERATOR>

Regards,

Sandeep

Edited by: Alvaro Tejada Galindo on Apr 10, 2008 6:02 PM

[Former Member]

Hi,

READ for any Internal Table

Reads a line of an internal table.

Syntax

READ TABLE <itab> FROM <wa>

|WITH TABLE KEY <k1> = <f1>... <kn> = <fn>

|WITH KEY = <f>

|WITH KEY <k1> = <f1>... <kn> = <fn>

INTO <wa> [COMPARING <f1> <f2>... |ALL FIELDS]

[TRANSPORTING <f1> <f2>... |ALL FIELDS|NO FIELDS]

|ASSIGNING <FS>

|REFERENCE INTO <dref>.

This statement reads either the line of the internal table with the same key as specified in the work area <wa>, the line with the key specified in the TABLE KEY addition, the line that corresponds fully to <f>, or the one corresponding to the freely-defined key in the KEY addition. The contents of the line are either written to the work area <wa>, or the line is assigned to the field symbol <FS>. If you assign the line to a work area, you can compare field contents and specify the fields that you want to transport.

READ for Index Tables

Reads a line of an internal table.

Syntax

READ TABLE <itab> INDEX <idx> INTO <wa>...

| ASSIGNING <FS>

| REFERENCE INTO <dref>.

The line with index 7 is read. The result is specified as with any internal table

Regards,

Priya.

[Former Member]

Hi,

u can u the stmt READ TABLE itab WITH KEY k1 = v1 ... kn = vn .

[Former Member]

hi,

you can use this codes too :

SORT ITAB BY NAME1 LAND1.

READ TABLE ITAB INTO WA_ITAB WITH KEY NAME1 = 'VICKY'

LAND1 = 'INDIA' BINARY SEARCH.

IF SY-SUBRC EQ 0.

PERFORM YOUR_STEPS.

ENDIF.

[Former Member]

Hi,

Use this:

Sort it_tab by name1 land1.

Read table it_tab into wa_tab with key name1 = 'Vicky'

land1 = 'India'

binary search.

if sy-subrc eq 0.

l_kunnr = wa_itab-kunnr.

endif.

hope it will help you.

Thanks,

Parul.

[Former Member]

Hi,

You can do as below using read statement:

sort itaby by name land1.

read table itab with key name1 = 'vicky' 
                                    land1 = 'india'.

if sy-subrc eq 0.
"Your necessary code
endif.

Thanks,

Sriram Ponna.

[Former Member]

Hi,

decalre an internal table and an explicit work area for that.

loop at it.

ReaD TABEL (INTERNAL TABLE NAME) INTO wa with key kunnr = 'VICKY' and land1 = 'INDIA'.

append wa.

modify itab from wa.

clear wa.

endloop.

write : wa-kunnr, wa-land1.

[Former Member]

Hi,

Read table itab with key name1 = 'vicky' and land1 = 'india'.

Thank u,

Manjula Devi.D

[soumya_jose3]

Hi,

Read table itab with key name1 = 'vicky' and land1 = 'india'.

Regards,

Soumya.

[Former Member]

HI,

If your internal table has more than one Record with values:

Name = Vicky and Land = India.

Read statement will fetch the First index with above condition.

If you want to read a particular record with above combination , you should modify ur Read statement with key condition.

Else it will b OK

Thanks

Praveen