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problem with back and exit button

Former Member
0 Likes
447

hI all

can you guys check the code and let me know where iam going wrong.

I have created back and exit of function type E.

WHEN I RUN THE TRANSACTION AND ENTER TO THE SCREEN 9002. AND THEN PRESS BACK,IT TAKES ME TO SCREEN 0.

tHATS FINE FOR ME.

bUT THE PROBLEM IS WHEN I ENTER THE NAME WRONG OTHER THAN SSSS

THEN I WOULD GET THE ERROR SAYING ENTER THE CORRECT NAME.

NOW WHEN I TRIED TO COME OUT OF THE SCREEN,IT WON'T ALLOW ME TO COME OUT.

PLEASE LET ME KNOW.

MODULE USER_COMMAND_9002_EXIT.

CHAIN.

FIELD Ztest-name MODULE CHECK_name_9002.

endchain.

MODULE USER_COMMAND_9002.

MODULE USER_COMMAND_9002_EXIT INPUT.

CASE OK_CODE.

WHEN 'BACK'.

LEAVE TO SCREEN 0.

WHEN 'EXIT'.

LEAVE TO SCREEN 0.

ENDCASE.

ENDMODULE. " USER_COMMAND_9002_EXIT INPUT

MODULE CHECK_name_9002 INPUT.

if ztest-name ne 'SSSS'.

MESSAGE E123(00) WITH 'Enter the correct name'.

ENDIF.

ENDMODULE. " CHECK_name_9002 INPUT

1 ACCEPTED SOLUTION
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venkata_ramisetti
Active Contributor
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412

Hi,

wrong statement:

MODULE USER_COMMAND_9002_EXIT.

correct statement:

MODULE USER_COMMAND_9002_EXIT at exit-command.

Thanks,

Ramakrishna

2 REPLIES 2
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venkata_ramisetti
Active Contributor
0 Likes
413

Hi,

wrong statement:

MODULE USER_COMMAND_9002_EXIT.

correct statement:

MODULE USER_COMMAND_9002_EXIT at exit-command.

Thanks,

Ramakrishna

Read only

0 Likes
412

Hi Ramakrishna,

Thanks

IT WORKS NOW.

IAM AWARDING FULL POINTS TO YOU.