problem on itab

[Former Member]

hello abapers,

in my scenario,

there are two itabs, itab1, itab2.

itab1 has name, marks. as fields.

itab2 has name, marks, sid, fields.

now i have to loop at itab1 and for every name in itab1 i have to check for that name entry in itab2, if found change that marks of that name entry with the itab1 marks. and if not found make a new entry with that name and marks.

can some one help me with this.

does modify help here if entry not found and we have to create a new one.

thank you.

[Former Member]

loop at itab1.

loop at itab2 where name = itab1-name.

move itab1-marks to itab2-marks.

modify itab2.

endloop.

if sy-subrc <> 0.

move itab1-name to itab2-name.

move itab1-marks to itab2-marks.

append itab2.

clear itab2.

endloop.

[Former Member]

Something like:

SORT: itab1 BY name,
      itab2 BY name.

LOOP AT itab1.
  READ TABLE itab2 WITH KEY 
    name = itab1-name
    BINARY SEARCH.
  IF sy-subrc = 0.
    itab2-marks = itab1-marks.
    MODIFY itab2 INDEX sy-tabix.
  ELSE.
    MOVE-CORRESPONDING itab1 TO itab2.
    APPEND itab2.
  ENDIF.
ENDLOOP.

Rob

Corrected READ

Message was edited by:

Rob Burbank

[Former Member]

loop at itab2.

lv_tabix = sy-tabix.

read table itab1 with key name = itab2-name.

if sy-subrc = 0.

itab2-marks = itab1-marks.

modify itab2 index lv_tabix.

else.

itab2-marks = <new marks>.

insert itab2 index lv_tabix.

endif.

endloop.

Regards,

Ravi

[Former Member]

See the logic,

you can use modify command..

data : begin of itab1 occurs 0,

name type c,

marks type c,

end of itab1.

data : begin of itab2 occurs 0,

name type c,

marks type c,

sid type c,

end of itab2.

start-of-selection.

loop at itab1.

read table itab2 with key name = itab1-name.

if sy-subrc ne 0.

• fill your values

modify itab1.

endif.

endloop.

Reward Points if it is useful

Thanks

Seshu