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Problem in sum a field through select command

Former Member
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1,170

Dear Sir(s),

I want to sum kbetr (no. of packing) for same knumv(invoice no.) in table konv.

e.g.

invoice no. no. of packing

(knumv) (kbetr)

001 2

001 3

002 4

002 5

result should be -

invoice no no. of packing

001 5

002 9

code-

select knumv kschl sum(distinct kbetr)

from konv

into table it_konv

for all entries in it_vbrk

where kschl = 'ZFQT'

and knumv = it_vbrk-knumv

group by knumv kbetr.

error showing - unkown col. sum(distinct field list.

Please help me immediately.

thanks,

R.Kapoor

1 ACCEPTED SOLUTION
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Former Member
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1,016

u can use at end of statement inside loop statement

loop at it.

write:/ it-field1,it-field2,

at end of kumnv

sum.

endat.

endloop.

reward points if this is useful

9 REPLIES 9
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FredericGirod
Active Contributor
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1,016

select knumv sum( kbetr )

into table it_konv

from ...

group by knumv.

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Former Member
0 Likes
1,017

u can use at end of statement inside loop statement

loop at it.

write:/ it-field1,it-field2,

at end of kumnv

sum.

endat.

endloop.

reward points if this is useful

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varma_narayana
Active Contributor
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1,016

Hi..

Change ur Select statement as below .

<b>select knumv sum(kbetr)</b>

from konv

into table it_konv

for all entries in it_vbrk

where kschl = 'ZFQT'

and knumv = it_vbrk-knumv

<b>group by knumv .</b>

Here you need not to Retrieve the Field KSCHL since it is anyway given in the WHERE clause.

Let me know incase of any other issue.

<b>Reward if Helpful.</b>

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1,016

Dear Sir,

I am still facing problem in using sum agregate in select statement.

it showing error again, kindly check at your end and send by mail.

thanks & regards,

Rakesh Kapoor

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Former Member
0 Likes
1,016

Hi,

try this

<b>select knumv kschl

from konv</b>

into table it_konv

for all entries in it_vbrk

where kschl = 'ZFQT'

and knumv = it_vbrk-knumv

group by knumv kbetr.

sort it_know by knumv.

loop at it_knov.

at end of knumv.

sum.

write:/ it_knov-knumv, it_knov-kbetr.

endat.

endloop.

thanks & regards,

Venkatesh

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Dear Sir,

Your solution is very helpful and now i overcome from the problem. hope in future also you will help me in solving problems.

thanks & regards,

Rakesh Kapoor

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Former Member
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1,016

u loop the internal table and then use

ON CHANGE OF in loop and do SUM.

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Former Member
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1,016

data:

it_konv2 like table of it_konv with header line.

select knumv kschl kbetr

from konv

into table it_konv

for all entries in it_vbrk

where kschl = 'ZFQT'

and knumv = it_vbrk-knumv.

loop at it_konv.

it_konv2 = it_konv.

collect it_konv2.

endloop.

**So it_konv2 will have your desired data.

Reward points if useful.Get back in case of query...

Cheers!!!

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Former Member
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1,016

Hi Rakesh,

Use collect statement.

Regards

Arun