MACRO

[Former Member]

Can someone explain this what exactly this piece of code is coding. i am not that much clear with macros.

DEFINE build_select.
     if not &1[] is initial.
       lt_select-tag = '&2'.
       loop at &1.
         move-corresponding &1 to lt_select.
         collect lt_select.
       endloop.
     endif.
   END-OF-DEFINITION.

Thanks

Pavan.N

[FredericGirod]

Hi,

the code replace &1 with the first variable, &2 with the second variable ...

so you will find in other place of the code :  build_select  var1 var2.

the macro could not be debugged

regards

Fred

[Former Member]

Hi,

I am not clear..

this is the code ...can u give me the better idea.

DATA: lt_display   TYPE TABLE OF ZIFSSTFL WITH HEADER LINE.,

         lr_kostl    TYPE TABLE OF zselstr WITH HEADER LINE,
        lt_select   TYPE TABLE OF ztrssopt WITH HEADER LINE.

DEFINE build_select.
     if not &1[] is initial.
       lt_select-tag = '&2'.
       loop at &1.
         move-corresponding &1 to lt_select.
         collect lt_select.
       endloop.
     endif.
   END-OF-DEFINITION.

   build_select lr_kostl kostl.
   build_select s_pernr  pernr.

thanks.

Pavan.N

[Former Member]

Hi Pavan,

- In above code, the statement "build_select lr_kostl kostl" means you are calling above defined MACRO with statement DEFINE....END-OF-DEFINATION.

- So when the statement "build_select lr_kostl kostl" is called then at runtime, the code will replace &1 with 'lr_kostl' and &2 with 'kostl' so your code at run time will be :

   build_select lr_kostl kostl.

    if not lr_kostl[] is initial.
       lt_select-tag = 'kostl'.
       loop at lr_kostl.
         move-corresponding lr_kostl to lt_select.
         collect lt_select.
       endloop.
     endif.

And in "build_select s_pernr  pernr" statement.

   build_select s_pernr  pernr.

     if not s_pernr[] is initial.

       lt_select-tag = 'pernr'.

       loop at s_pernr.

         move-corresponding s_pernr to lt_select.

         collect lt_select.

       endloop.

     endif.

[former_member209120]

Hi Pavan,

See this link to learn about macros

http://help.sap.com/saphelp_nw2004s/helpdata/en/9f/db972835c111d1829f0000e829fbfe/content.htm

DATA: result TYPE i,
       n1     TYPE i VALUE 5,
       n2     TYPE i VALUE 6.

DEFINE operation.
   result = &1 &2 &3.
   output   &1 &2 &3 result.
END-OF-DEFINITION.

DEFINE output.
   write: / 'The result of &1 &2 &3 is', &4.
END-OF-DEFINITION.

operation 4 + 3.
operation 2 ** 7.
operation n2 - n1.

his produces the following output: 

The result of 4 + 3 is          7

The result of 2 ** 7 is        128

The result of N2 - N1 is          1

[Former Member]

This is how macro works.

data: begin of itab occurs 0,

            col1(2),

            col2(5),

            col3(3),

         end of itab.

define ex.

   itab = &1.

end-of-definition.

start-of-selection.

  ex 'Wedonotlie'.

.....

The above code will pass 'Wedonotlie' to &1 in macro ex. After assigning &1 to itab,

we will have itab-col1 = 'We', itab-col2 = 'donot' and itab-col3 = 'lie'

In your example, the code moves field values of internal table (&1)  to corresponding fields of lt_select.

for all records of &1 it will assign &2 to <tag field> of lt_select . It collects the rows of lt_select as and when it is appended.

So somewhere in main program you might have statement like

build_select it_mara 'MAT'.

above will pass internal table it_mara as &1 and 'MAT' as &2 to macro build_select.

Got it ?

Regards,

Vishram

Why it is still under moderation ? Even after 3 hours ?

Message was edited by: Vishram Kendurkar Why it is stll under consideration by moderator ?

[Former Member]

Assuming macro is called like this:

build_select var1 var2.

var1 is internal table that is being looped into.

var2 contains value for field tag of table lt_select.

Macro will populate lt_select-tag with var2.

Common fields of record var1 will be populated into var2.

And then there is a collect statement which will append or modify record of lt_select.