it values

[Former Member]

Dear Experts,

I have an iternal table like below

F1 F2 F3

1 W 90

2 S 78

3 D 90

4 5 45

5 8 87

My requirement is i need to keep the lines which contains maximum values in F3

in the above example i need only the line F3 = 90. remaining should delete

i need like below

F1 F2 F3

1 W 90

3 D 90

Can anyone send code for this.

thanks in advance

[uwe_schieferstein]

Hello Karthik

Here is a possible solution for your problem:

DATA:
  ls_entry   LIKE LINE OF it_itab.

SORT it_itab by field_f3 descending.
READ TABLE it_itab INTO ls_entry INDEX 1.

DELETE it_itab WHERE ( field_f3 < ls_entry-field_f3 ).

Regards

Uwe

[Former Member]

sort itab by F3 descending.

read table itab into w_area index 1.

delete itab where F3 < w_area -f3.

[Former Member]

Karthik,

Sort itab by F3 descending.

read itab index 1 into WA.

delete itab where F3 ne WA-F3.

Rgds,

Sarah.

[Former Member]

Hi,

you can try this:

data:aux_internal like your_table occurs 0 with header line.

sort your_table by F3 descending.

if not your_table[] is initial.

read your_table index 1 into aux_internal.

delete your_table where F3 <> aux_internal-F3.

endif.

[Former Member]

sort itab by F3 descending.

loop at itab.
  at end of F3.
    flag = 'X'.
  endat.
  if flag eq 'X'.
    delete itab.
  endif.
endloop.

[Former Member]

delete itab where f3 ne 90.

This code will work for sure.

Pls reward points if its useful.

Regards,

Sujatha.

[Former Member]

Hi,

Try this

SORT itab descending by F3.

READ TABLE itab WITH index 1.
 IF sy-subrc  = 0.
 v_val = itab-f3.
DELETE itab WHERE f3 NE v_val.
 ENDIF.

[Former Member]

karthik... i have taken your example.. just copy and see.

DATA: BEGIN OF ITAB OCCURS 0,

F1 TYPE I,

F2(1),

F3 TYPE I,

END OF ITAB.

DATA: SNO TYPE I.

ITAB-F1 = 1.

ITAB-F2 = 'W'.

ITAB-F3 = 90.

APPEND ITAB.

ITAB-F1 = 2.

ITAB-F2 = 'S'.

ITAB-F3 = 78.

APPEND ITAB.

ITAB-F1 = 3.

ITAB-F2 = 'D'.

ITAB-F3 = 90.

APPEND ITAB.

ITAB-F1 = 4.

ITAB-F2 = '5'.

ITAB-F3 = 45.

APPEND ITAB.

ITAB-F1 = 5.

ITAB-F2 = '8'.

ITAB-F3 = 87.

APPEND ITAB.

SORT ITAB BY F3 DESCENDING.

READ TABLE ITAB INDEX 1.

SNO = ITAB-F3.

DELETE ITAB WHERE F3 LT SNO.

LOOP AT ITAB.

WRITE : / ITAB-F1, ITAB-F2, ITAB-F3.

ENDLOOP.

[Former Member]

Assuming ur internal table as itab1

sort itab1 by F3 descending.

clear l_f3.

loop at itab1 into wa_itab1.

if sy-tabix = 1.

l_F3 = wa_itab2-f3.

else.

if wa_itab2 LT L_F3

l_index = sy-tabix.

exit.

endif.

endif.

endloop.

describe itab1 lines n.

delete itab1 from l_index to n.

I hope it helps.

Best Regards,

Vibha

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