internal tables

[Former Member]

Hi friends,

I have two internal tables t_tab1 and t_tab2 which are of different structures.

1.t_tab1has the following fields

A_tab1 B_tab1 C_tab1 D_tab1....etc

2.t_tab2 has the following fields,

A_tab2 B_tab2 C_tab2 D_tab2....etc

3.t_tab2 is sorted according to the field B_tab2.

The Key btw the two table is A .(A_tab1 = A_tab2)

Eg.

t_tab1

A_tab1 B_tab1

01.01.2007 1

02.02.2007 2

03.03.2007 3

04.04.2007 4

t_tab2 before sort

A tab2 Btab2

01.01.2007 01.01.2007

02.02.2007 20.01.2007

03.03.2007 3.01.2007

04.04.2007 4.01.2007

sort t_tab2 by B.

t_tab2 after sort

A_tab2 B_tab2

01.01.2007 01.01.2007

03.03.2007 3.01.2007

04.04.2007 4.01.2007

02.02.2007 20.01.2007

Now i want to sort t_tab1 also in this order .

ie.

I want t_tab1 in the following order.

A_tab1 B_tab1

01.01.2007 1

03.03.2007 3

04.04.2007 4

02.02.2007 2

How to sort t_tab1 in the above order.

Points will be given for helpful answers.

Thanks.

Ramya

[Former Member]

declare itab3 same structure of itab1.

loop at itab2

read table itab1 with key A_ita1 = A_itab2 binary search.

if sy-subrc EQ 0.

itab3 = itab1.

append itab1

clear ita1.

endif.

endloop

refresh itab1.

itab1[] = itab3[].

[Former Member]

declare itab3 same structure of itab1.

loop at itab2

read table itab1 with key A_ita1 = A_itab2 binary search.

if sy-subrc EQ 0.

itab3 = itab1.

append itab1

clear ita1.

endif.

endloop

refresh itab1.

itab1[] = itab3[].

[Former Member]

declare itab3 same structure of itab1.

loop at itab2

read table itab1 with key A_ita1 = A_itab2 binary search.

if sy-subrc EQ 0.

itab3 = itab1.

append itab3

clear ita3.

endif.

endloop

refresh itab1.

itab1[] = itab3[].

[Former Member]

Hi,

pass t__tab1 to a temp t_temp.

Loop at t_tab2.

read t_temp comparing t_tab2-a_tab and t_temp-a_tab.

pass to t_tab1.

endloop.

Reward if useful.

Regards,

Bindu.

[Former Member]

Create another table itab3 of type itab1.

then use this.

loop at t_itab2.

read table itab1 with key A = t_itab2-A

if sy-subrc = 0.

move-corresponding itab1 to itab3.

append itab3.

endif.

endloop.

[JozsefSzikszai]

hi Ramya,

I think you need another internal table like tab1 (let's call it tab1_copy)

*after sorting of tab2, you go through tab2:

LOOP AT tab2.

*look for the proper recors from tab1

READ TABLE tab1 WITH key a = tab2-a.

*append the record to tab1_copy

APPEND tab1 TO tab1_copy.

ENDLOOP.

afte this in tab1_copy you have the records sorted acc. to tab2 sorting. Of course you can do as well:

tab1[] = tab1_copy[].

Now you have the proper order in tab1.

hope this helps

ec

[Former Member]

define another table tab3 like tab1 and then you can sort data in tab1 like your requirement...

e.g.

data:

t_tab3 like table of t_tab1 with header line.

loop at t_tab2.

read table t_tab1 with key A_tab1 = t_tab2-A_tab2.

if sy-subrc eq 0.

append t_tab1 to t_tab3.

delete t_tab1.

endif.

endloop.

append lines of t_tab1 to t_tab3.

clear: t_tab1,t_tab1[].

t_tab1[] = t_tab3[].

now tab1 will hav sorted data as in tab2.

Reward points if useful, get back in case of query...

Cheers!!!

[Former Member]

Hi

This can be solved in the below mentioned way.

1. After sorting the second table. Read the second table with the condition that the A_tab2 = A_tab1. append that work area into a new internal table.After that you can refresh the first internal table and then t_tab1[] = new internal table.

The first internaltable will have the fields in the order similar to that of second internal table.

Thanks

Mohit