‎2007 Dec 18 7:09 AM
Hi All,
I am unable to get the desired out put from this 'IF' condition, the scenario is if I put ABC in f_name and execute the program without giving l_name it should print 'ABC XYZ' but it is not working...
Kindly help
parameters: f_name(20) type c.
l_name(20) type c.
write:/ f_name.
l_name.
if f_name eq 'ABC'.
write:/'ABC XYZ'.
endif.
‎2007 Dec 18 7:11 AM
hi
Reetesh
try like this
parameters: f_name(20) type c.
l_name(20) type c.
write:/ f_name,
l_name.
if I_name is initial.
write:/'ABC XYZ'.
endif.
plzzz reward if usefull dontforget to reward
‎2007 Dec 18 7:15 AM
Hi,
Its working fine. try like this:
parameters: f_name(20) type c,
l_name(20) type c.
if f_name eq 'ABC'.
write:/'ABC XYZ'.
endif.
write:/ f_name,
l_name.
Regards,
Bhaskar
‎2007 Dec 18 7:16 AM
Hi,
I am able to get the output
ABC
ABC XYZ
with the below code.
parameters: f_name(20) type c,
l_name(20) type c.
write:/ f_name, l_name.
if f_name eq 'ABC'.
write:/'ABC XYZ'.
endif.
‎2007 Dec 18 7:21 AM
Thanks Guys,,
Jayanti it is working now I wonder what was wrong... ))