Hi expert. replace . with space

[Former Member]

HI expert.

I want to replace '.' with space . so I proceed below.

itab is composed to two feilds.

date1 type char10

date2 type char10

the field's values are '2011.01.01'.

REPLACE ALL OCCURRENCES OF REGEX '\b(.)\b'

IN TABLE ITAB WITH SPACE

RESPECTING CASE.

result.

date1 : '2011010120'

date2 : '110101'

but I want the result below.

date1 : '20110101'

date2 : '20110101'

what should i do?

please help.

[Former Member]

HI expert.

I want to replace '.' with space . so I proceed below.

itab is composed to two feilds.

date1 type char10

date2 type char10

the field's values are '2011.01.01'.

REPLACE ALL OCCURRENCES OF REGEX '\b(.)\b'

IN TABLE ITAB WITH SPACE

RESPECTING CASE.

result.

date1 : '2011010120'

date2 : '110101'

but I want the result below.

date1 : '20110101'

date2 : '20110101'

what should i do?

please help.

[Former Member]

Hi,

As u mention ur date is 2011.01.01 u want to make it as 20110101 as use the FM CONVERT_DATE_TO_INTERNAL.

REGARDS,

ZAFAR

[Former Member]

BUT there are so many data in the table.

[Former Member]

Check with separted by word

[Former Member]

Hi Jake,

Using convert date to internal as mentioned by Zafar is a good idea, i don't see how this concerns the no of records, do update the post if you have a special requirement/concerns about using that FM.

Anyways the other way to do it using the offsets,

data: l_data type char10 value '2011.01.01',
l_date2 type char10.

concatenate l_data+0(4)  l_data+5(2) l_data+8(2) into l_date2.

or 

l_date2+0(4) = l_data+0(4).
l_date2+8(2) = l_data++5(2).
l_date2+8(2) = l_data+8(2).

Regards,

Chen

[ravi_lanjewar]

Try this.

data: l_data type char10 value '2011.01.01',
l_date2 type char10.

concatenate l_data+0(4)  l_data+5(2) l_data+8(2) into l_date2 sepArated by space.

write l_date2.