Find a '(' in a string?

[Former Member]

Hello,

I have the following code.

DATA: tmp TYPE STRING,
      result TYPE i.

tmp = 'Craig (Cmehil)'.
IF tmp CS '('.
  result = 1.
ENDIF.

write: / result.

IF tmp NS '('.
  result = 0.
ENDIF.

write: / result.

However the result should be 1 and then 0 but I get 1 and then 1 again.

How can I find the ( inside of a string?

[Former Member]

DATA: tmp TYPE STRING.

tmp = 'Craig (Cmehil)'.

write: / tmp.

IF tmp CA '#('.
  tmp = 'Found'.
ELSE.
  tmp = 'Not Found'.
ENDIF.

write: / tmp.

Sometimes sitting back and thinking and you get that whole apple on the head realization

[MalaGo]

Hi,

you can use SEARCH f FOR g to find string g in string f.

Regards,

Malgorzata

Message was edited by: Malgorzata Jaworek

[Former Member]

Hi,

you will not get a 1 in second case.

just think over again. what you are trying is in the first instance trying to see if the '(' is part of the string. which is yes, so it goes in ans set result to 1.

But in the second case you set result to 0 only when the string shouldn't contain '('. But since in your case it contains '(' it won't go in.

[Former Member]

Actually the logic in the first post was completely wrong but my second post shows how I solved my own problem. Just didn't have my eyes open is all

[Former Member]

Hello Craig,

Use following statement. It works allways.

if ls_text CP '('.

do soething.

endif.

BR

Michael

[Former Member]

Hi,

There is one more option, this will also work

IF char CN '+-*/=~#^[]\&%$@.,;:"!}{'.

-- do the job --

ENDIF

Prabhu Rajesh.