Error de Dato no compatible

[ricardjavier]

Hola, podrian ayudarme a resolver este inconveniente?

Tengo el error de tipo de dato no compatible entre el lifnr y el s_id.

***********************************************************************************************

FORM get_list_vendors

CHANGING ex_zlfa1 TYPE zlfa1_tab.


SELECT *
FROM zlfa1
INTO TABLE @DATA(list_vendors)
WHERE lifnr = @s_id.

IF sy-subrc EQ 0.

"save list.

ex_zlfa1 = list_vendors.

ELSE.
"error

CLEAR ex_zlfa1.


ENDIF.


ENDFORM.

[ricardjavier]

Hola, podrian ayudarme a resolver este inconveniente?

Tengo el error de tipo de dato no compatible entre el lifnr y el s_id.

***********************************************************************************************

FORM get_list_vendors

CHANGING ex_zlfa1 TYPE zlfa1_tab.


SELECT *
FROM zlfa1
INTO TABLE @DATA(list_vendors)
WHERE lifnr = @s_id.

IF sy-subrc EQ 0.

"save list.

ex_zlfa1 = list_vendors.

ELSE.
"error

CLEAR ex_zlfa1.


ENDIF.


ENDFORM.

[vipinsaraika]

Hi Ricardo,

Can you please make sure that data type for S_id is same as the filed LIFNR of table LFA1

Or else define it as below

data: s_id type lfa1-lifnr.

[Sandra_Rossi]

Usually people like to prefix selection screen range fields with "S_", so I guess you declared S_ID like that:

TABLES zlfa1.
SELECT-OPTIONS s_id FOR zlfa1-lifnr.

If so, instead of "=", use "IN" (because "S_ID" is like a range table):

SELECT * FROM zlfa1 INTO TABLE @DATA(list_vendors) WHERE lifnr IN @s_id.

[ricardjavier]

Muchas gracias Vipin, efectivamente ya tenía declarada la variable " SELECT-OPTIONS s_id FOR zlfa1-lifnr."

Muchas gracias Sandra, efectivamente mi codigo solo cambie el " = " por el " IN " y funcionó.

Muy Agradecido por su ayuda!