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Dynamic values

Former Member
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1,000

Guys,

Data: var type i,

chhar(10) type c.

do 3 times.

add 1 to var.

chhar = 'CHARACTER( var )'.

WRITE: / chhar.

enddo.

I want the output as

CHARACTER1

CHARACTER2

CHARACTER3.

but im unable to do it. Could anyone please help me out. I donot want to use concatenate.

Thanks,

Santosh.

12 REPLIES 12
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rejish_balakrishnan
Contributor
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977

Hi,

Data: var type c,
chhar(9) type c,
char(9) type c value 'character'.

do 3 times.
add 1 to var.
chhar = char.

WRITE  :  chhar .
write  : 10 var.
skip .

enddo.

Please check if it does meet your requirement.Otherwise please feel to reply in wt condition u want that required output.

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Pawan_Kesari
Active Contributor
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977

DATA: var TYPE i,
chhar(10) TYPE c.

DO 3 TIMES.
  chhar = sy-index .
  CONDENSE chhar .
  CONCATENATE 'CHARACTER' chhar into chhar .
  WRITE: / chhar.
ENDDO.
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Former Member
0 Likes
977

Data: var(1) type N,

ch type C,

chhar(10) type c.

do 3 times.

add 1 to var.

ch = var.

concatenate 'CHARACTER' ch into chhar.

WRITE: / chhar.

enddo.

Regards

Sandip

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former_member156446
Active Contributor
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977

try this way:

DATA: var TYPE i,
chhar(10) TYPE c.

DO 3 TIMES.
  ADD 1 TO var.
  chhar+0(9) = 'CHARACTER'.
  chhar+9(1) = var.
  WRITE: / chhar.
ENDDO.

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Former Member
0 Likes
977

No Guys,

I said No Concatenate. How do we assign it dynamically.

Thanks,

Santosh.

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0 Likes
977

>

> I said No Concatenate. How do we assign it dynamically.

>

my reply has no concatenate..

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0 Likes
977

Thank you so much Jay for ur answer but i am looking for something like this

chhar = 'CHARACTER( var )'. but not offsets or concatenation.

Thanks,

Santosh.

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0 Likes
977

Maybe you could use REPLACE, if you know the var name, do you know?

Regards

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0 Likes
977

>

> but not offsets or concatenation.

>

Hi, you are like the business team, don't say all at once.... Kidding I doubt if its possible without offset or concatenate...

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0 Likes
977

Hi,

Did u try the code written by me.Just to know whether u had a look at it !

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Pawan_Kesari
Active Contributor
0 Likes
977

Could you explain the actual problem.. or is that a interview question?

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former_member222860
Active Contributor
0 Likes
977

Try

Data: var type i.

var = 0.
Do 3 times.
add 1 to var.
WRITE: /'CHARACTER ', var .
Enddo.