2007 Feb 21 10:17 AM
hi experts,
DATA: temp(20) VALUE 'DATA',
i TYPE I VALUE 1,
J(2) type c.
LOOP AT l_t_tsi.
J = I.
CONCATENATE TEMP J INTO COLNAME.
itab-(COLNAME) = l_t_tsi-time_series_value.
i = i + 1.
ENDLOOP.
My internal table (itab) has fields data1(20), data2(20), data3(20)...
I want to generate the column names dynamically only.
The above code gives an error at this line -
itab-(COLNAME) = l_t_tsi-time_series_value.
Thanks in advance,
Bijal
hi experts,
DATA: temp(20) VALUE 'DATA',
i TYPE I VALUE 1,
J(2) type c.
LOOP AT l_t_tsi.
J = I.
CONCATENATE TEMP J INTO COLNAME.
itab-(COLNAME) = l_t_tsi-time_series_value.
i = i + 1.
ENDLOOP.
My internal table (itab) has fields data1(20), data2(20), data3(20)...
I want to generate the column names dynamically only.
The above code gives an error at this line -
itab-(COLNAME) = l_t_tsi-time_series_value.
Thanks in advance,
Bijal
2007 Feb 21 10:19 AM
2007 Feb 21 10:20 AM
its not possible in this fashion. but if you tell us what you want do by doing this, may be we could come up with better option
2007 Feb 21 10:22 AM
hi,
mentioning colname gives itab does not contain colname field.
thanks
2007 Mar 26 9:23 AM
Hi,
If your aim is to refer to a internal table field dynamically you can do it.
Look at the code segment below -
DATA: temp(20) VALUE 'DATA',
i TYPE I VALUE 1,
J(2) type c.
FIELD-SYMBOLS: <ls_data>.
LOOP AT l_t_tsi.
J = I.
CONCATENATE TEMP J INTO COLNAME.
<b>ASSIGN COMPONENT colname OF itab TO <ls_data>.
<ls_data> = l_t_tsi-time_series_value.</b>
*itab-(COLNAME) = l_t_tsi-time_series_value.
i = i + 1.
ENDLOOP.
Regards,
Manish Joshi
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