doubt on data types ( cnipf dtx)

[Former Member]

data : a1 type i .

now howmany values can i hold it seems it can hold 4 bytes .

1 byte = 8 bits

1bit = 1 / 0

so 8 bits = 8 * 1 = 8 (abcdefgh)

so 4 bytes = 4 * 8 = 32 bits.

it means a1 can hold 9999999999999999999999999999999

please explain if it is not true.

[Former Member]

data : a1 type i .

now howmany values can i hold it seems it can hold 4 bytes .

1 byte = 8 bits

1bit = 1 / 0

so 8 bits = 8 * 1 = 8 (abcdefgh)

so 4 bytes = 4 * 8 = 32 bits.

it means a1 can hold 9999999999999999999999999999999

please explain if it is not true.

[varma_narayana]

Hi ..

Data type I (Integer) can hold max 10 digit numbers.

Here 4 bytes does not mean you can store upto 32 digits value.

but the calcuation is like

for 1 byte it can store max 2 power 8 values = 256

like that 4 bytes means maximum 2 power 32 .

beyond that limit raises an ARITHMETIC_OVERFLOW exception.

Hope this gives the idea.

<b>Reward for helpful solutions.</b>

[Former Member]

1 byte = 8 bits

1bit = 1 / 0

so 8 bits = 8 * 1 = 8 (abcdefgh)

so 4 bytes = 4 * 8 = 32 bits.

in this 32 bits one bit is reserved for sign ( + or -) now in the remaining 31 bits you can use for storing the value i.e is maximum 2^31 - 1 = 2147483647( i.e. yuou can put 1 or 0 for any bit and by binary to decimal conversion it comes 2147483647).

generally the range is from -2147483648 to 2147483647 for an integer.

regards

shiba dutta