divide fields from 2 tables

[Former Member]

hallow

i have 2 difrent tables (itab_1,itab_2)with fields from a1....a12 and i wont to divide all the fields from itab_1 and itab_2 and put them in itab 3

what is the best way to do that

i give example

itab1

a1--a2-a3---a4.....

10--20-30---40

itab2

b1--b2b3---b4......

2----2--4-----5

<b>itab3 <----

---

result of divide fileds c1=a1/b1</b>

c1--c2c3---c4......

5----10-7.5--8

Regards

<b>i reward</b>

[Former Member]

HI,

do like this.

loop at itab1.

read table itab2 index sy-index.

itab3-c1 = itab1-a1 / itab2-b1.

itab3-c2 = itab1-a2 / itab2-b2.

itab3-c3 = itab1-a3 / itab2-b3.

itab3-c4 = itab1-a4 / itab2-b4.

append itab3.

endloop.

reward if helpful

rgds,

bharat.

[Former Member]

Hi!

If you don't have keys in the tables, but the lines are exatly in the same row, then you could use this way:

LOOP AT it1.

READ TABLE it2 INDEX sy-tabix.

CLEAR it3.

it3-c1 = it1-a1 / it2-b1.

it3-c2 = it1-a2 / it2-b2.

...

APPEND it3.

ENDLOOP.

Regards

Tamá

[Former Member]

data: my_tabix like sy-tabix.

loop at itab1.

my_tabix = sy-tabix.

read table itab2 index my_tabix.

if sy-subrc eq 0.

itab3-c1 = itab1-a1 / itab2-b1.

itab3-c1 = itab1-a1 / itab2-b1.

itab3-c1 = itab1-a1 / itab2-b1.

....

append itab3

endif.

endloop.

Reward points if useful, get back in case of query...

Cheers!!!

Message was edited by:

Tripat Pal Singh

[Former Member]

Try this,

loop at t_a.

read TABLE t_b index sy-index.

t_c-c1 = t_a-a1 / t_b-b1.

t_c-c2 = t_a-a2 / t_b-b2.

t_c-c3 = t_a-a3 / t_b-b3.

append t_c.

ENDLOOP.

Regards,

Vimal

[Former Member]

Forget everything,

Just use:

DIVIDE-CORRESPONDING ITAB1 BY ITAB2.

• Plz reward if u find it useful

[Former Member]

Hi

loop at itab1.
my_tabix = sy-tabix.
read table itab2 index my_tabix.
if sy-subrc eq 0.
itab3-c1 = itab1-a1 / itab2-b1.
itab3-c1 = itab1-a1 / itab2-b1.
itab3-c1 = itab1-a1 / itab2-b1.
....
append itab3
endif.
endloop.

reward if usefull

[Former Member]

Hi

or try like this

LOOP AT itab1.
READ TABLE itab2 INDEX sy-tabix.
itab3-c1 = itab1-a1 / itab2-b1.
itab3-c2 = itab1-a2 / itab2-b2.
itab3-c3 = itab1-a3 / itab2-b3.
itab3-c4 = itab1-a4 / itab2-b4.
APPEND itab3.
CLEAR itab3
ENDLOOP.

reward if useful