Count the values

[Former Member]

Hai Friends,

1 A 10

1 A 20

1 A 30

1 B 30

1 B 20

1 C 20

I want the count of 1st column when there is a change in second column. That is,

1 A 10

1 A 20

1 A 30 count is 3

1 B 30

1 B 20 count is 2

1 C 20 count is 1

Thanks.

[uwe_schieferstein]

Hello

The itab must be sorted accordingly:

DATA: ld_sum             TYPE i,
DATA: ls_record         LIKE LINE OF lt_itab,
DATA: ls_record_old  LIKE LINE OF lt_itab.

  SORT lt_itab BY column2.
  
  ld_sum = 0.
  READ TABLE lt_itab INTO ls_record_old INDEX 1.
  LOOP AT lt_itab INTO ls_record.

    IF ( ls_record-column2 = ls_record_old-column2 ).
     ADD ls_record-column1 TO ld_sum.
    ELSE.
      " NOTE: Here you have store the value of LD_SUM somewhere

      ld_sum = ls_record-column1.
    ENDIF.

    ls_record_old = ls_record.
  ENDLOOP.

Regards

Uwe

[Former Member]

Hi,

You can keep the logic simple by this approach.

Step 1: Sort the internal table by the 2nd Column.

Step 2: By processing the individual lines of the internal table you can track the changes.

The code extract is given below:

Data : Count type i value 0.

Loop at itab.

at new column2.

count = 0.

endat.

count = count + 1.

• your own logic here.

endloop.

Hope this helps.

Thanks,

Samantak.

[Former Member]

Hi,

Please check this

DATA: BEGIN OF itab OCCURS 0,
        f1 TYPE char10,
        f2 TYPE char10,
        f3 TYPE char10,
      END OF itab.

DATA: count TYPE i.

itab-f1 = '1'.
itab-f2 = 'A'.
itab-f3 = '10'.
APPEND itab.

itab-f1 = '1'.
itab-f2 = 'A'.
itab-f3 = '20'.
APPEND itab.

itab-f1 = '1'.
itab-f2 = 'A'.
itab-f3 = '30'.
APPEND itab.

itab-f1 = '1'.
itab-f2 = 'B'.
itab-f3 = '30'.
APPEND itab.

itab-f1 = '1'.
itab-f2 = 'B'.
itab-f3 = '20'.
APPEND itab.

itab-f1 = '1'.
itab-f2 = 'C'.
itab-f3 = '20'.
APPEND itab.

count = 0.
LOOP AT itab.
  WRITE:/ itab-f1, itab-f2, itab-f3.
  count = count + 1.
  AT END OF f2.
    WRITE:/'Count is ', count.
    CLEAR count.
  ENDAT.

ENDLOOP.