conversion of exponential value to integer

[Former Member]

Hello All,

I have a requirement wherein i need to convert a value in exponential notation to integer value. The details are below :

DATA: L_ATFLV LIKE AUSP-ATFLV.

if L_ATFLV holds a value 1. 1.1100000000000000E+00

then it should be converted to a value 1.11

2 . if 1.1100000000000000E+03

then it should be converted to 1110.00

TIA,

Helpful ans will be rewarded

[Former Member]

Hi,

just equate the field to a variable of type P decimals 2.

and print the variable. the variable will have the value as 1.11 for the first case and 1100.00 for the second case.

Regards,

Aswin

[Former Member]

try this:

data f type f.

data: i type i.

data c(20) type c value '7.77E-10'.

call function 'CHAR_FLTP_CONVERSION'

exporting string = c

importing flstr = f.

i = f.

write: f.

write: i.

Message was edited by: kishan negi

[suresh_datti]

try KKEK_CONVERT_FLOAT_TO_CURR.

Regards,

Suresh Datti

[Former Member]

hi,

Declare a variable of type P and assign the same to that variable.

data: var type <b>p.</b>

var = value.

regards,

Santosh

[Former Member]

YOu can use the write statement using the exponent addition.

REPORT zh_test1 NO STANDARD PAGE HEADING.

DATA float TYPE f value '1.1100000000000000E+03'.

WRITE (6) float EXPONENT 0.

Regards,

Ravi

[Former Member]

Hi Sharat,

Almost all data types are inter convertible..

So just assign it to a floating point variable and your query is solved.

Just check this code..

data: a type ausp-atflv.

data: b type p decimals 2.

a = '1.1100000000000000E+00'.

b = a .

write b.

Regards,

SP.

[Former Member]

try this

data : integer type i.

integer = exponent.----->(exponential variable)

[Former Member]

Try this...

data: f like AUSP-ATFLV.

data: p type p decimals 2.

f = '1.1100000000000000E+03'.

p = f.

write: f, p.

[Former Member]

Dear Sharat,

Please check this thread Simple routine to convert exponential values to float that solves this issue.

Regards,

Mohammed Mohsen