‎2007 May 18 12:02 PM
Hi all,
I have two internal tables say itab1 and itab2 as follows.
Itab1
kschl Gl no
Cond1 10229
Cond2 10988
Cond3 1228
Cond4 12977
Cond5 1467
Cond6 86888
Cond7 97008
itab2
Kunwe kschl
111 Cond1
111 Cond2
111 Cond3
112 Cond1
112 Cond4
113 Cond3
113 Cond5
i have to compare these two internal tables and i have to catch the condition types which are missing in itab2 for each kunwe.(for eg. for kunwe=111 the missing condition types are cond4,cond5,cond6,cond7)
kindly help me.
Thanks,
Praveena.
means
‎2007 May 18 12:07 PM
Hi
declare another itab with kunwe, kschl.
Loop at ITAB2.
read table itab1 with kschl = itab2-kschl.
if sy-subrc = 0.
delete itab1 index sy-tabix.
endif.
endloop.
Now ITAB1 will have the condition types that are missing for ITAB2 KUNWE.
Reward points if useful
Regards
Anji
‎2007 May 18 12:07 PM
Hi
declare another itab with kunwe, kschl.
Loop at ITAB2.
read table itab1 with kschl = itab2-kschl.
if sy-subrc = 0.
delete itab1 index sy-tabix.
endif.
endloop.
Now ITAB1 will have the condition types that are missing for ITAB2 KUNWE.
Reward points if useful
Regards
Anji
‎2007 May 18 12:07 PM
HI,
DATA: itab3 like itab1.
Loop at itab1 into wa_itab1.
READ TABLE itab2 into wa_itab2 with key kschl = wa_itab1-lschl.
if sy-subrc<>0.
append wa_itab1 into itab3.
endif.
endloop.
Regards,
Sesh
‎2007 May 18 12:17 PM
Hi
Try the following code given below.
delete adjacent duplicates from itab2 comparing kunwe.
loop at itab2.
loop at itab1.
if itab1-kschl <> itab2-kschl.
append itab2-kunwe to temp-kunwe.
append itab1-kschl to temp-kschl.
endif.
endloop.
endloop.
Hope this helps u.
Reward if helpful.
Thanks & regards,
Prakash Ghantasala
‎2007 May 18 12:20 PM
hi,
create a internal table with required fields as
data; begin of itab3 occurs 0,
lschl like itab2-lschl [ database-field name]
................
end of itab.
Loop at itab1 into wa_itab1.
READ TABLE itab2 into wa_itab2 with key kschl = wa_itab1-lschl.
if sy-subrc<>0.
append wa_itab1 into itab3.
endif.
endloop.
if helpful reward some points.
with regards,
suresh babu aluri.
‎2007 May 18 12:22 PM
i am giving u the solution as per the example u have given.
itab3 [] = itab2[].
sort itab2 by kunwe.
sort itab3 by kunwe.
loop at itab2.
on change of itab2-kunwe.
loop at itab3
where kunwe <> itab2-kunwe.
endloop.
endon.
endloop.
Please reward some points if Useful.
Regards,
Padmakar