Check a parameter in a ranges table

[arkantos]

HI,

Can anyone tell me what is wrong with the following code.

IF NOT P_KUNNR IS INITIAL.

* **       IF P_KUNNR NOT BETWEEN R_KUNNR-LOW AND R_KUNNR-HIGH.

         IF P_KUNNR NOT IN R_KUNNR.

           R_KUNNR_LINE-SIGN = 'I'.

           R_KUNNR_LINE-OPTION = 'EQ'.

           R_KUNNR_LINE-LOW = P_KUNNR.

           APPEND R_KUNNR_LINE TO R_KUNNR.

         ENDIF.

ENDIF.

When P_KUNNR is not inital and R_KUNNR was not containing P_KUNNR, mycode does not pass through the ranges statements.

[arkantos]

HI,

Can anyone tell me what is wrong with the following code.

IF NOT P_KUNNR IS INITIAL.

* **       IF P_KUNNR NOT BETWEEN R_KUNNR-LOW AND R_KUNNR-HIGH.

         IF P_KUNNR NOT IN R_KUNNR.

           R_KUNNR_LINE-SIGN = 'I'.

           R_KUNNR_LINE-OPTION = 'EQ'.

           R_KUNNR_LINE-LOW = P_KUNNR.

           APPEND R_KUNNR_LINE TO R_KUNNR.

         ENDIF.

ENDIF.

When P_KUNNR is not inital and R_KUNNR was not containing P_KUNNR, mycode does not pass through the ranges statements.

[rosenberg_eitan]

Hi,

What is the content of R_KUNNR ?

Was it empty ?

regards. 

[VenkatRamesh_V]

Hi,

Try this,

IF NOT P_KUNNR IS INITIAL.

          IF ( P_KUNNR  NOT IN  R_KUNNR[] ) OR ( R_KUNNR[] IS INITIAL ).

            R_KUNNR_LINE-SIGN = 'I'.

            R_KUNNR_LINE-OPTION = 'EQ'.

            R_KUNNR_LINE-LOW = P_KUNNR.

            APPEND R_KUNNR_LINE TO R_KUNNR.

       ENDIF.

ENDIF.

Hope it helpful,

Regards,

Venkat.

[arkantos]

Thanks Eitan and Venkat for your response..

Issue solved venkat..

As you have pointed out we have to check both conditions.

When R_KUNNR is an empty table P_KUNNR  NOT IN  R_KUNNR[]  alone is not sufficient.

Thanks..

[matt]

If you define R_KUNNR correctly (i.e. as RANGE OF) then you do not need the []