char string processing

[Former Member]

I have 2 materials A99\ and A99\260. If the last char of the material is \ gv_bulk is 'X'. Can someone help me with the code. Thank you

[aaron_morden2]

DATA mat1 TYPE matnr VALUE `a99`.

SHIFT mat1 RIGHT DELETING TRAILING ' '.

IF mat1+17 = ''.
  gv_bulk = 'X'.
ENDIF.

[Former Member]

First get the string length, then check the last character.

DATA: len TYPE i.

len = strlen( material ) - 1.

IF material+len = '\'.

gv_bulk = 'X'.

ENDIF.

[Former Member]

data : lv_material(20) type c,

len type i,

lv_lastchar type c.

lv_material = 'Material\'.

len = strlen( lv_material ).

len = len - 1.

lv_lastchar = lv_material+len(1).

if lv_lastchar eq '\'.

gv_bulk = 'X'.

endif.

[ferry_lianto]

Hi,

Please try this.

DATA: WA_MATNR TYPE MARA-MATNR VALUE `A99260`.

SEARCH WA_MATNR FOR ''.

IF SY-SUBRC = 0.
  GV_BULK = 'X'.
ELSE.
  ...
ENDIF.

Regards,

Ferry Lianto