ALV average calculation without zero values

[Former Member]

Hi Experts,

I am using the ALV grid for report output, able to get the average values and it's working fine.

User wants the average calculation only for non-zero values, meaning...

1st row = 50.00

2nd row = 20.00

3rd row = 0.00

4th row = 40.00

5th row = 0.00

In this case current output is '110.00 / 5 = 22. it's working fine.

User requriement is 110 / 3 = 36.67. Is this functionallity possible in ALV ?.

Let me know your valueable suggestion.

Thanks

Raj

[Former Member]

Hi,

Did you find the solution for this request (ALV average calculation without zero values). If so, can you please send the details.

[Former Member]

Hi raj,

Do not go for the standard totalling or average function in the ALV.

instead do the math in your internal table only and have it as a the last line/

like

loop at itab.
if itab-value <> 0.00.
v_total = v_total + itab-value.
count = count + 1.
endif.
at last.
v_average = v_total / count.
clear itab.
itab-value = v_average.
append itab.
endat.
endloop.

[Former Member]

>In this case current output is '110.00 / 5 = 22. it's working fine.

>User requriement is 110 / 3 = 36.67. Is this functionallity possible in ALV ?.

It is not possible. you need to do that manually and show it at the end.

[Former Member]

From ALV you cannot do this.

Instead you need to calculate the average using the values in tables.

And then use it to display.;

Regards,

Lalit Mohan Gupta.

[Former Member]

Hi,

I want calculate the percentage of subtotal values in the same row in alv grid report.

Is this functionality is possible...

Plz let me your suggestion.

[Former Member]

Hi,

Did you find the solution for this request (ALV average calculation without zero values). If so, can you please send the details.

[Former Member]

Hi,

Please check this below logic.

clear count.

loop at itab.

if not itab-value = '0.00'.

count = count + 1.

endif.

at last.

v_average = v_total / count.

itab-value = v_average.

append itab.

endat.

endloop.