Adding hours/day to a date

[Former Member]

Hello,

I have field of length 20 which contains date in the format “mm/dd/yyyy hh:mm:ss”.

I want to add 5 hrs, 8 hrs, 2 days to this date value depending upon some condition.

Can anyone please suggest how to do this or any FM which does this.

Thanks in advance

[Former Member]

Hello,

I have field of length 20 which contains date in the format “mm/dd/yyyy hh:mm:ss”.

I want to add 5 hrs, 8 hrs, 2 days to this date value depending upon some condition.

Can anyone please suggest how to do this or any FM which does this.

Thanks in advance

[Former Member]

splite into two logic.

hour.

calcu the hour.

24 = 1day.

day.

add that day with result.

[Former Member]

Hi..

DATA : FA(20) TYPE c,

FB(10) TYPE c,

FC TYPE d,

FD(8) TYPE c,

FE TYPE t.

data : f_m(10) type c,

f_d(10) type c,

f_y(10) type c,

f_h(10) type c,

f_mi(10) type c,

f_s(10) type c,

f_aa(10) type c,

f_bb(10) type c.

FA = '07/01/2007 08:09:10'.

SPLIT fa AT space INTO f_aa f_bb.

SPLIT f_aa AT '/' INTO f_m f_d f_y.

SPLIT f_bb AT ':' INTO f_h f_mi f_s.

• add your logic...

i want to help you.

regards..

[Former Member]

Hi,

If you want to use FM, then try FM RP_CALC_DATE_IN_INTERVAL.

data: wa_date like sy-datum.

call function 'RP_CALC_DATE_IN_INTERVAL'

exporting

date = sy-datum

days = 13

months = 0

signum = '+'

years = 0

importing

calc_date = wa_date.

write: / wa_date.

<b>Reward points if this helps,</b>

Kiran

[Former Member]

hi jeet,

try using end_time_determine