ABAP 7.4 (read table)

[DKanna]

TYPES: BEGIN OF ty_final,
         ebeln TYPE ekko-ebeln,
         bukrs TYPE ekko-bukrs,
         ebelp TYPE ekpo-ebelp,
       END OF ty_final.

DATA: lt_final TYPE TABLE OF ty_final,
      ls_final TYPE ty_final.

SELECT ebeln, bukrs FROM ekko INTO TABLE @DATA(lt_ekko) UP TO 5 ROWS.

IF sy-subrc = 0.
  SELECT ebeln, ebelp FROM ekpo INTO TABLE @DATA(lt_ekpo)
     FOR ALL ENTRIES IN @lt_ekko WHERE ebeln = @lt_ekko-ebeln.
ENDIF.

SORT: lt_ekko BY ebeln,lt_ekpo BY ebeln.

LOOP AT lt_ekpo INTO DATA(ls_ekpo).
  ls_final-ebeln = ls_ekpo-ebeln.
  ls_final-ebelp = ls_ekpo-ebelp.

*  READ TABLE lt_ekko INTO DATA(ls_ekko) WITH KEY ebeln = ls_ekpo-ebeln BINARY SEARCH.

data(ls_ekko) = lt_ekko[ ebeln = ls_ekpo-ebeln ]."Binary search not working

  IF sy-subrc = 0.
    ls_final-bukrs = ls_ekko-bukrs.
  ENDIF.
  APPEND ls_final TO lt_final.

ENDLOOP.

cl_demo_output=>display( lt_final ).

Hi,

How to use binary search in read table for the new ABAP 7.4

[DKanna]

You cannot use the BINARY SEARCH addition with the new expression. Even if you could, you should not. Use a sorted table type, so the lookup of records will always be accessed via binary search algorithm implicitly.

DATA: lt_ekko TYPE SORTED TABLE OF ekko WITH UNIQUE KEY ebeln.

[Former Member]

You cannot use the BINARY SEARCH addition with the new expression. Even if you could, you should not. Use a sorted table type, so the lookup of records will always be accessed via binary search algorithm implicitly.

DATA: lt_ekko TYPE SORTED TABLE OF ekko WITH UNIQUE KEY ebeln.

[Sandra_Rossi]

NB: the answer is ambiguous ("cannot use [the binary search] with the new expression" (table expression)) because in fact when the table is of type SORTED a table expression uses the binary search algorithm implicitly (if the components match the key), so you mean that the two words "BINARY SEARCH" cannot be used explicitly in a table expression as they are with READ TABLE.

[Former Member]

sandra.rossi

Thanks, reading the answer after a day was in fact ambiguous. I was trying to say that whenever you have to type BINARY SEARCH it is a certain thing that you are using the wrong table type. 🙂

[FredericGirod]

You need to declare the internal table as sorted table.

[mlizcano1]

Hi, I don´t know what is the error I execute the next code and work fine.

TYPES: BEGIN OF ty_final,
  ebeln TYPE ekko-ebeln,
  bukrs TYPE ekko-bukrs,
  ebelp TYPE ekpo-ebelp,
END OF ty_final.

DATA: lt_final TYPE TABLE OF ty_final,
      ls_final TYPE ty_final.

SELECT ebeln, bukrs FROM ekko INTO TABLE @DATA(lt_ekko) UP TO 5 ROWS.

IF sy-subrc = 0.
  SELECT ebeln, ebelp FROM ekpo INTO TABLE @DATA(lt_ekpo)
        FOR ALL ENTRIES IN @lt_ekko WHERE ebeln = @lt_ekko-ebeln.
ENDIF.

SORT: lt_ekko BY ebeln,lt_ekpo BY ebeln.


LOOP AT lt_ekpo INTO DATA(ls_ekpo).
  ls_final-ebeln = ls_ekpo-ebeln.
  ls_final-ebelp = ls_ekpo-ebelp.
  READ TABLE lt_ekko INTO DATA(ls_ekko) WITH KEY ebeln = ls_ekpo-ebeln BINARY SEARCH.

  IF sy-subrc = 0.
    ls_final-bukrs = ls_ekko-bukrs.
  ENDIF.
  APPEND ls_final TO lt_final.
  CLEAR ls_ekko.
ENDLOOP.

cl_demo_output=>display( lt_final ).

[raphael_almeida]

Hi dhanushkanna

About your statement:

data(ls_ekko) = lt_ekko[ ebeln = ls_ekpo-ebeln ]."Binary search not working

Beware with this type of table read... Sometimes when this internal table was initial or the line don't exists you'll get a dump...

Use Try Catch or this statement: DATA(ls_ekko) = VALUE #( lt_ekko[ ebeln = ls_ekpo-ebeln ] OPTIONAL ).