Replace the last character

[Former Member]

I have a requirement.....I have strinf for ex. INT,CHAR,BHB,BNVB,

I have to replace the last occurance of , into .

It will look like  INT,CHAR,BHB,BNVB.

Please help.

[Former Member]

Hi Sanghamitra,

You can do 2 things.

1. Reverse the string and use REPLACE FIRST OCCURRENCE statement.

2. Or else, search for the offset of last , and then replace that offset using REPLACE SECTION statement.

Hope it helps you.

Regards,

Sindhu Pulluru.

[Former Member]

Hi,

You can try the following:

data: v_str type string,

        l_lines type i.

v_str = ' INT,CHAR,BHB,BNVB,'.

Split v_str at ',' into table itab.

describe table itab lines l_lines.

read table itab into w_tab index l_lines.

if sy-subrc eq 0.

replace ',' with '.' in w_tab.

modify itab from w_tab index l_lines.

endif.

[UweFetzer_se38]

Why so complicated if you can make it simple?

REPLACE REGEX ',$' in gv_string WITH '.'.

Best regards

[rafaelfp]

Very nice hint! But I had to use '.$' instead of ',$' to make it work.

[mayur_priyan]

Hi,

You can try the following

   data: lv_data TYPE string value 'int,ban,sit,viu,',
      lv_len TYPE i,
      lv_data1 TYPE char25.

lv_data1 = lv_data.
lv_len = strlen( lv_data ).
lv_len = lv_len - 1.
lv_data1+lv_len(1) = '.'.
write: / lv_data.
        skip.
write: / lv_data1.

[Former Member]

Hello Sanghamitra,

When you say 'last occurrence...' does that mean the last character? If so, Uwe's statement (and Mayur's code) would work.

But if the below string qualifies for your idea of 'last occurrence' then the solutions given by Uwe and Mayur won't work.

INT,CHAR,BHB,BNVB

Can you clarify?

-Amit.

[Former Member]

Note the date of the OP.

Rob

[Former Member]

Oops...