XML - change element/node name

[Former Member]

Hi,

I'm using this function to generate the data to dom.

CALL FUNCTION 'SDIXML_DATA_TO_DOM'

EXPORTING

NAME = 'ACCESOS'

DATAOBJECT = ACCESOS[]

IMPORTING

DATA_AS_DOM = L_DOM

CHANGING

DOCUMENT = M_DOCUMENT

EXCEPTIONS

ILLEGAL_NAME = 1

OTHERS = 2.

IF SY-SUBRC = 0.

WRITE 'Ok'.

ELSE.

WRITE: 'Err =',

SY-SUBRC.

ENDIF.

My issue is when i'm using this function it will generate the xml in this format

<?xml version="1.0" encoding="utf-8" ?>

- <ACCESOS>

- <item>

- <SOCIO>

<NUMERO>00045050</NUMERO>

<REPOSICION>0</REPOSICION>

<NOMBRE>MOISES MORENO</NOMBRE>

- <TURNOS>

<LU>T1</LU>

<MA>T2</MA>

<MI>T3</MI>

<JU>T4</JU>

<VI>T5</VI>

<SA>T6</SA>

<DO>T7</DO>

</TURNOS>

</SOCIO>

</item>

</ACCESOS>

May I know how could I change the "<item" and "</item>" description to "<testing>" and "</testing>". Kindly help me on this.

Thanks.

[Former Member]

Hi

Check this link:

Check this link:

http://www.devguru.com/technologies/xmldom/quickref/node_nodeName.html

Regards

Neha

Edited by: Neha Shukla on Nov 30, 2008 9:51 AM

[uwe_schieferstein]

Hello

You can do a simple XML-XML transformation using the following XSLT stylesheet:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

    <xsl:output encoding="UTF-8" method="xml" indent="yes"/>

    <xsl:template match="*">
        <xsl:apply-templates select="self::*" mode="copy"/>
    </xsl:template>
    
    <xsl:template match="item">
        <xsl:element name="testing">
            <xsl:apply-templates />           
        </xsl:element>
    </xsl:template>

    <xsl:template match="*" mode="copy">
        <xsl:copy>
            <xsl:apply-templates/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="text()">
        <xsl:value-of select="."/>
    </xsl:template>

</xsl:stylesheet>

Regards

Uwe